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MissTica
3 years ago
12

Help me please help help help​

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0
What is your question?
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On a coordinate plane, 2 lines are shown. Line P Q has points (negative 8, 2) and (4, 2). Line M N has points (8, 6) and (8, neg
DaniilM [7]

Answer:

Slope of PQ = 0

Slope of MN = infinity

PQ and MN are perpendicular to each other

Step-by-step explanation:

for any two points  (x1, y1),  (x2, y2)given in coordinate plane slope is given by

y1 - y2/x1-x2\\\\For \ line \ PQ\\slope = 2 - 2/-8-4 = 0\\\\For \ line \ MN \\slope = 6 - (-8)/8-8 = 1/0 = infinity\\\\

For any line if slope is zero it is parallel  to X axis and perpendicular to Y axis

For any line if slope is infinity it is parallel  to Y axis and perpendicular to X axis

Also we know X and Y are perpendicular to each other.

Since slope of PQ is zero it is parallel  to X axis and perpendicular to Y axis

Since slope of MN is infinity it is parallel  to Y axis and perpendicular to X axis.

Thus two lines PQ and MN are perpendicular to each other.

4 0
3 years ago
Read 2 more answers
Find the volume of a pyramid with a square base, where the area of the base is
natima [27]

Answer:

303.3 ft

Step-by-step explanation:

16.3ft²÷2=8.15

then V = LWH/3

(Length, width and height over 3)

then round up

7 0
3 years ago
Find the sum.<br> (5p+11) + (8p- 4)<br> A. 5p+7<br> B. 13p-7<br> C. 13p+7<br> D. 13p+15<br> AP3X
USPshnik [31]

Answer:

(5p + 11) + (8p - 4) \\ = ( 13p + 7)

<h2>C. (13p+7) is the right answer.</h2>
6 0
3 years ago
Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor
kenny6666 [7]

Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) Standard deviation of 23 bags

\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)

= 1 - P(z < 12.57)

Calculation the value from standard normal z table, we have,  

P(x < 5.95) = 1 - 1 = 0

c) P( fill volume of 23 bags is below 6 ounces)  = 0.001

P(x < 6)  = 0.001

P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})

Calculation the value from standard normal z table, we have,  

P( z \leq -3.09) = 0.001

\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

7 0
3 years ago
mauricio estimates that the first module of the project could be completed in as few as 15 days or could take as many as 25 days
4vir4ik [10]

Answer:

<em>Most likely time, </em>according to PERT (Program evaluation and review technique).

Step-by-step explanation:

PERT is "a statistical tool used in <em>project management" (Program evaluation and review technique (2020), </em>in Wikipedia), and it is commonly used with CPM <em>(Critical Path Method)</em> to manage projects.

Inside PERT, there are different defined times to accomplished an activity in a project, that is:

  • An <em>optimistic time</em> or minimum time required to accomplished an activity, i.e., if everything goes better than normal, the activity is accomplished before expected.
  • A <em>pessimistic time, </em>a time quite the opposite to optimistic time.
  • A <em>most likely time</em>, or a time required to accomplished an activity if everything goes as expected or normally.
  • An <em>expected time</em>, an statistical estimation.

Considering the question, we have that the <em>time</em> when "the first module of the project could be completed":

  • "[...] in as few as 15 days"  is the <em>optimistic time</em>.
  • "[...] or could take as many as 25 days" is the <em>pessimistic time</em>.
  • "[...] but most likely will require 20 days" is the <em>most likely time</em>.

As a result, the <em>20-day estimate</em> is called the <em>most likely time</em> in the context of the PERT/CPM techniques.

3 0
3 years ago
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