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3 years ago

4 yd. 8 in + 6 yd. 6 in

Mathematics

2 answers:

Alex73 [517]3 years ago

4 0

10 yd and 14 inches is the common answer for that

Sunny_sXe [5.5K]3 years ago

3 0

Answer: 10 yd. 14 in.

Step-by-step explanation:

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How do you solve this math problem of ratio?

Alex17521 [72]

I don't know, this is tricky

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2 years ago

Select the correct answer from the drop-down menu. Consider this system of linear equations: y − x = -13 -4x + 3y = -51 The solu

Nookie1986 [14]

Answer:

Step-by-step explanation:

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2 years ago

The system without any solutions sets is called

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Answer: B.inconsistent

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2 years ago

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Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi

natta225 [31]

Answer:

b. circle; $2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

Step-by-step explanation:

The given conic has equation;

$x^2-5x+y^2=3$

We complete the square to obtain;

$(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}$

This is a circle with center;

$(\frac{5}{2},0)$

This implies that;

$x=\frac{5}{2},y=0$

When the circle is rotated through an angle of $\theta=\frac{\pi}{3}$ ,

The new center is obtained using;

$x'=x\cos(\theta)+y\sin(\theta)$ and $y'=-x\sin(\theta)+y\cos(\theta)$

We plug in the given angle with x and y values to get;

$x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3})$ and $y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})$

This gives us;

$x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}$

The equation of the rotated circle is;

$(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}$

Expand;

$(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}$

Multiply through by 4; to get

$4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37$

Write in general form;

$4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0$

Divide through by 2.

$2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

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2 years ago

How do i add 21p to 35q

mariarad [96]

I don't think you can because the variables are different. You can only add the same variables.

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2 years ago

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