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arlik [135]
4 years ago
11

Find the equation in standard form of the line passing through the points (2,-3) and (4,2)

Mathematics
1 answer:
Sonja [21]4 years ago
5 0

The equation of the line passing through the points (x_1,y_1) and (x_2,y_2) is

\frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1}. Here \frac{y_1-y_1}{x_2-x_1} is the slope of the line.

Substituting numerical values,

\frac{x-2}{y+3} =\frac{4-2}{2+3} \\ \frac{x-2}{y+3} =\frac{2}{5} \\ 5x-10=2y+6\\ 5x-2y-16=0

The equation of the line in standard form is 5x-2y-16=0.

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