The complete question is this: This figure (Figure 1) shows a container that is sealed at the top by a movable piston. Inside the container is an ideal gas at 1.00 atm, 20.0 ∘C, and 1.00 L. This information will apply to the first three parts of this problem.
A) What will the pressure inside the container become if the piston is moved to the 1.20 L mark while the temperature of the gas is kept constant?
Explanation:
It is given that,
= 1 atm,
= 1 L
= ? ,
= 1.20 L
As the temperature is constant. Hence, find the value of
as follows.
= 
= 
= 0.833 atm
Thus, we can conclude that the pressure inside the container is 0.833 atm.
Answer:
You have to sub x in for the number you dont know and then solve for x.
Explanation:
10(5+x)=90
50+10x=90
10x=40
x=4
Acceleration, a = (v - u) / t
Initial Velocity, u = 30 m/s
Final Velocity, v = 23 m/s
time t = 2.00 seconds
a = (23 - 30) / 2
a = -7 / 2 = -3.5 m/s2
So the acceleration is negative, which means it is a deceleration of 3.5 m/s2.
True, nuclear reactions, whether they are fission or fusion depend on generating energy by converting a certain amount of mass by breaking the atom or combining two atoms together.