The tension on the wire is 52.02 N.
From the question, we have
Density of aluminum = 2700 kg/m3
Area,
A = πd²/4
A = π x (4.6 x 10⁻³)²/4
A = 1.66 x 10⁻⁵ m²
μ = Mass per unit length of the wire
μ = ρA
μ = 2700 kg/m³ x 1.66 x 10⁻⁵ m²
μ = 0.045 kg/m
Tension on the wire = √T/μ
34 = √T/0.045
34² = T/0.045
T = 52.02 N
The tension on the wire is 52.02 N.
Complete question:
The density of aluminum is 2700 kg/m3. If transverse waves propagate at 34 m/s in a 4.6-mm diameter aluminum wire, what is the tension on the wire.
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Answer:
<h2>33.53m/s</h2>
Explanation:
Given the maximum speed limit on interstate 10 as 75 miles per hour, to get the speed in meter per seconds, we need to convert the given speed to meter per seconds.
Using the conversion 1 mile = 1609.34m and 1 hour = 3600 seconds
75 miles perhour = 75miles/1 hour
75miles/1 hour (in m/s) = 75miles*1609.34m* 1 hour/1mile * 1 hour * 3600s *
= 75 *1609.34m* 1 /1 * 1 * 3600s
= 120,700.5m/3600s
= 33.53m/s
<em>Hence the maximum speed limit on interstate 10 in metre per seconds is 33.53m/s</em>
matter is a solid liquid or gas , a atom is a basic unit of a chemical element and a molecule is a group of atoms together
Answer:
Explanation:
1760 yd/mi / 120 yd/field = 14⅔ fields/mi
Current in the wire = 2 A
Explanation:
the magnetic field is given by
B= \frac{\mu i}{2\pi r}
μo= 4π x 10⁻⁷ Tm/A
i= current
r=0.02 m
B = magnetic field= 2 x 10⁻⁵ T
2 x 10⁻⁵= (4π x 10⁻⁷)(i) / (2π*0.02)
i=2 A
