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3 years ago

Can anyone answer this question for me please..

Physics

1 answer:

motikmotik3 years ago

8 0

Answer:

You have to sub x in for the number you dont know and then solve for x.

Explanation:

10(5+x)=90

50+10x=90

10x=40

x=4

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A woman can see clearly with her right eye only when objects are between 45 cm and 155 cm away. Prescription bifocals should hav

Yuri [45]

Answer:

Explanation:

given,

A woman can see object between 45 cm and 155 cm

glasses is 2 cm from the eye

to able to read a book distance = 25 cm

For the object distant apart

$\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}$

$\dfrac{1}{f}= \dfrac{1}{\infty}+\dfrac{1}{-153}$

$\dfrac{1}{f} = - 6.53 \times 10^{-3}$

hence, D = - 0.653 m

For the object at the near point

$\dfrac{1}{f}= \dfrac{1}{p} +\dfrac{1}{q}$

$\dfrac{1}{f}= \dfrac{1}{23} +\dfrac{1}{-43}$

$\dfrac{1}{f}= 0.0202 cm$

hence, D = 2.02 m

8 0

3 years ago

A circular loop of radius r carries a current i. at what distance along the axis of the loop is the magnetic field one-half its

lana [24]

At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

<h3>What is the formula to calculate the Magnetic field intensity due to a current carrying circular loop at a point on its axis?</h3>

The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

$B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }$

Now, for magnetic field intensity at the center of the loop can calculated by putting x = 0 in the above equation. On solving, we get -

$B(0) = \frac{\mu_{o} i}{2R}$

Let us assume that the distance at which the magnetic field intensity is one-half its value at the center of the loop be ' r '. Then -

$\frac{\mu_{o} iR^{2} }{2(r^{2} +R^{2})^{\frac{3}{2} } } = \frac{1}{2} \frac{\mu_{o}i }{2R}$

$2R^{3} = (r^{2} +R^{2} )^{\frac{3}{2} }$

$4R^{6} = (r^{2} +R^{2} )^{3}$

$r^{2} =0.587R^{2}$

r = 0.766R

Hence, at r = 0.766 R - the magnetic field intensity will be half of its value at the center of the current carrying loop.

To solve more questions on magnetic field intensity, visit the link below-

brainly.com/question/15553675

#SPJ4

6 0

2 years ago

If there is no change in the velocity of the object then it is known to be in ______

irga5000 [103]

OPTION (C) IS CORRECT

ANSWER - UNIFORM MOTION

If there is no change in the velocity of the object then it is known to be in <u>UNIFORM MOTION</u>.

EXPLORE MORE:-

EXAMPLE - A CAR COVERS A DISTANCE OF 15 KM WE'D EVERY 2 HOURS

FOR AN UNIFORM MOTION, ACCELERATION IS ZERO , AS THERE IS NO CHANGE IN VELOCITY....

-THANKS.!!

4 0

2 years ago

write a good scientific question that can be answered by Guadalupe based on what is described above. Label the independent and d

kakasveta [241]

To do that, we would need to know what is "described above".

4 0

3 years ago

What the answer help mees

Vera_Pavlovna [14]

C. The membrane is inside the cell wall. The cell wall surrounds the membrane.

7 0

3 years ago

Can anyone answer this question for me please..​

Can anyone answer this question for me please..