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Tju [1.3M]
3 years ago
14

A cyclist rides 6.3 km east for 21 minutes, then he turns and heads west for 6 minutes and 1.8 km. Finally, he rides east for 13

.2 km, which takes 44 minutes. (Assume motion toward the east is positive. Indicate the direction with the signs of your answers.) What is the final displacement of the cyclist?
Physics
1 answer:
Leona [35]3 years ago
6 0

Answer:

\vec{d}=17.7km

Explanation:

Displacement is a vector that defines the position of a particle. The vector extends from the initial position to the final position. Therefore, the displacement only takes into account this positions, since its trajectory is not important:

\vec{d}=6.3km-1.8km+13.2km\\\vec{d}=17.7km

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Steam at 4 MPa and 400C enters a nozzle steadily with a velocity of 60 m/s, and it leaves at 2 MPa and 300C. The inlet area of
frez [133]

Answer:

(A) 4.09 kg/s

(B) 589.9 m/s

(C)   0.0008707 m^{3} =  8.71 cm^{2}

Explanation:

inlet pressure of steam (P1) = 4 MPa

inlet temperature of steam (T1) = 400 degree celcius

inlet velocity (V1) = 60 m/s

outlet pressure (P2) = 2 MPa

outlet temperature (T2) = 300 degree celcius

inlet area (A1) = 50 cm^{2} = 0.005 m^{2}

rate of heat loss (Q) = 75 kJ/s

(A) mass flow rate (m) = \frac{A1 x V1}{α1}

where the initial specific volume (α1) for the given temperature and pressure is gotten from tables A-6 = 0.07343 m^3/kg

m = \frac{0.005 x 60}{0.07343}

m = 4.09 kg/s

(B) we can get the outlet velocity using the energy balance equation

  E in = E out

   m(h1 + \frac{(V1)^{2}}{2}) =  m(h2 + \frac{(V2)^{2}}{2})

V2 = \sqrt{2(h1 - h2) +(V1)^{2} - 2\frac{Q}{m}

where h1 and h2 are the enthalpies and are gotten from table A-6

V2 = \sqrt{2 x 1000 x(3214.5 - 3024.2) +(60)^{2} - 2\frac{75 x 1000}{4.09}

V2 = 589.9 m/s  

(C) the outlet area is gotten from mass flow rate (m) = \frac{A2 x V2}{α}

  A2 = (α2 x m) / V2

where the initial specific volume (α2) for the given temperature and pressure is gotten from tables A-6 = 0.12552 m^3/kg

A2 = (0.12552 x 4.09) / 589.5 = 0.0008707 m^{3} =  8.71 cm^{2}

4 0
3 years ago
Shawn and his bike have a total mass of
Trava [24]

Answer:

Shawn's kinetic energy is 61.45 J.

Explanation:

Given;

Mass of the system is, m=52.3\ kg

Displacement of the bike is, d=1.6\ km=1.6\times 1000=1600\ m

Time taken is, t=17.4\ min=17.4\times 60=1044\ s

Let the constant velocity be v.

For constant velocity, magnitude of velocity is given as distance by time.

Therefore, v=\frac{d}{t}=\frac{1600}{1044}=1.533\ m/s

Now, kinetic energy of a body is given as:

KE=\frac{1}{2}mv^2

Here, m=52.3\ kg,\ v=1.533\ m/s

\therefore KE=\frac{1}{2}\times 52.3\times (1.533)^2\\KE=0.5\times 52.3\times 2.35\\KE=61.45\ J

Therefore, Shawn's kinetic energy is 61.45 J.

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What three sprites are needed to create the Space Invaders game that was discussed in the unit? spaceship, laser, enemy gnome, a
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Answer: anlien, enemy gnome, spaceship

Explanation:

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