Answer:
Explanation:
Given that,
Mass of the heavier car m_1 = 1750 kg
Mass of the lighter car m_2 = 1350 kg
The speed of the lighter car just after collision can be represented as follows


b) the change in the combined kinetic energy of the two-car system during this collision

substitute the value in the equation above

Hence, the change in combine kinetic energy is -2534.78J
-- Momentum is (mass) x (speed).
Object B has 1.5 times as much momentum as Object A has.
-- Kinetic energy is (1/2) x (mass) x (speed) .
Object B has 1.5 times as much kinetic energy as Object A has.
-- If they would both stop long enough to get on the scale,
Object B would weigh 1.5 times as much as Object A does.
Answer:
F = 9.675Hz
Explanation:
pls for certain reasons let us make
- wavelength = $
- frequency = F
- V = velocity
3 loops : 6$/4 = L
6$/4 = 2
$ = 4/3 = 1.333
V = F x $
F = V/$
F = 12.9/1.333 = 9.675Hz
F = 9.675Hz
5 minutes is the minimum time