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3 years ago

Whats the answer to 2y^0-(3y)^0

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

6 0

Answer:

Step-by-step explanation:

To answer this question, we need to that any number (except zero) raised to power 0 is equal to 1. With that in mind, let's solve this:

2y^0 - (3y)^0

= 2(1) - (1)

= 1

Note: 2y^0 = 2(y^0) = 2(1) = 2 whereas

(2y)^0 = 1

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If 101! = (99!)x, then x = ?

beks73 [17]

$99!x=101!\ \ \ /:99!\\\\x=\frac{101!}{99!}\\\\x=\frac{99!\cdot100\cdot101}{99!}\\\\x=100\cdot101\\\\x=10\ 100$

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3 years ago

F(x)=-2x-1 and g(x)=x^2-1. Find (fog)(-5).

serg [7]

Answer: - 49

Step-by-step explanation:

f(x) = -2x - 1

g(x) = $x^{2}$ - 1

fg(x) = f ( $x^{2}$ - 1) , we just put in the value of g(x) , the next thing is to substitute $x^{2}$ - 1 for the value of x in f(x) , that is

fg(x) = -2( $x^{2}$ - 1) - 1

fg(x) = -2 $x^{2}$ + 2 - 1

fg(x) = -2 $x^{2}$ + 1

Therefore : fg(-5) means we will substitute -5 for x in fg(x) , that is

fg(-5) = -2 ( $(-5)^{2}$ + 1

fg(-5) = -2(25) + 1

fg(-5) = -50 + 1

fg(-5) = -49

7 0

3 years ago

Name the property. (6x4) x3 = 6x(4x3)

Helga [31]

Answer:

Associative

Step-by-step explanation:

When three or more numbers are multiplied, the product is the same regardless of the way in which the numbers are grouped.

6 0

3 years ago

Tell whether the ordered pair (- 3, 0) is a solution of the given system. - 2x + 2y >= 4an y >= 2x - 6

alukav5142 [94]

Answer:

The ordered pair is a solution.

Step-by-step explanation:

Plug x = -3 and y = 0 into the 2 inequalities and see if they fit:

-2x + 2y >= 4

-2(-3) + 2(0) = 6 which is > 4 so this one fits.

y>= 2x - 6

0 >= 2*-3) - 6 = -12 which also fits.

8 0

3 years ago

Read 2 more answers

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solniwko [45]

Answer:

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Step-by-step explanation:

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2 years ago