Add the equations,just the way they appear there.
-- Add the top 'x' to the bottom 'x'. Write the sum under the 'x's.
-- Add the '+y' and the '-y'. Write the sum under the 'y's.
-- Add the '2' and the '4'. Write the sum under them, with n " = " sign
before it.
You should now have an equation with only 'x' in it and no 'y'.
You can easily solve that one and find out the value of 'x'.
Once you know the value of 'x', go back to either one of the original
equations, and plug the number-value of 'x' in place of 'x'.
You'll then have an equation with only 'y' in it and no 'x'.
You can easily solve that one and find out the value of 'y'.
Answer:
gttrtyghuj
Step-by-step explanation:
Answer:
n = ±7
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define equation</u>
-3n² + 147 = 0
<u>Step 2: Solve for </u><em><u>n</u></em>
- Subtract 147 on both sides: -3n² = -147
- Divide -3 on both sides: n² = 49
- Square root both sides: n = ±7
Answer:
4.8 hours
Step-by-step explanation:
6=10$
divide by 10
0.6=1$
multiply by 8
4.8=8$
