Answer:
the frequency is the fundamental and distance is L = ¼ λ
Explanation:
This problem is a phenomenon of resonance between the frequency of the tuning fork and the tube with one end open and the other end closed, in this case at the closed end you have a node and the open end a belly, so the wavelength is the basis is
λ = 4 L
In this case L = 19.4 cm = 0.194 m
let's use the relationship between wave speed and wavelength frequency and
v = λ f
where the frequency is f = 440 Hz
v = 4 L f
let's calculate
v = 4 0.194 440
v = 341.44 m / s
so the frequency is the fundamental and distance is
L = ¼ λ
Answer:
(a) Magnitude of force is 262.51 N
(b) Angle with East direction is 
Explanation:
Force by Jack in vector form
Force by Jill in Vector form is given by
Force by Jane is
Net force is:
Hence
The net force will be given by
Since 
and 
The direction of net force is:
Since and
The angle with East direction is
Net force exerted on the donkey is in the south-east direction. So, the angle of net force from the east direction is and it is 
from the south.
2nd stone time = 13.0/9.8 = 1.33 seconds
distance = 0.5*9.8*1.33^2 = 8.67 meters
1st stone time = 1.33+1.5 = 2.83 seconds
distance = 0.5*9.8*2.83^2 = 39.24 meters
39.24-8.67 = 30.57 meters apart
The solution for this problem:
The distance in mega parsec is equal to recession velocity / H, where h is equal to 50 mega parsec.The explanation for this is:1 parsec = 2.E+05 AU, nearly. 50 mega parsec = 1. E+13 AU, nearly. 1 mega means E+06 (million).
