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3 years ago

12

A stone is dropped from the roof of a high building. a second stone is dropped 1.50 s later. how far apart are the stones when t

he second one has reached a speed of 13.0 m/s?

1 answer:

Aleksandr [31]3 years ago

3 0

2nd stone time = 13.0/9.8 = 1.33 seconds

distance = 0.5*9.8*1.33^2 = 8.67 meters

1st stone time = 1.33+1.5 = 2.83 seconds

distance = 0.5*9.8*2.83^2 = 39.24 meters

39.24-8.67 = 30.57 meters apart

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3 years ago

A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel

larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\$ (1)

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R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

$I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}$ (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

$R_{eq}=\frac{23V}{4A}=5.75\Omega$

Now, you can calculate the unknown resistor R2 by using the equation (1):

$\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega$

hence, the resistance of the unknown resistor is 10.31Ω

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3 years ago

Read 2 more answers

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Answer:

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3 years ago