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3 years ago

Finding a Job Math Quiz

1 answer:

7 0

Employer A hourly wage= 35,000$/52(weeks)=673.08$ per week. 673.08/40(hours)=16.82$ an hour. Therefore employer B offers more money at 37,440$ yearly

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yo can someone please help me out. school is rlly stressful and i just need help. the question is “find the perimeter and area o

Bess [88]

These will be the answers

6 0

3 years ago

Solve for x. y=a(x-h)^2+k

Natasha_Volkova [10]

Answer:

B ±sqrt((y-k)/a ) + h= x

Step-by-step explanation:

y=a(x-h)^2+k

Subtract k from each side

y-k = a(x-h)^2+k-k

y-k = a(x-h)^2

Divide by a

(y-k)/a = a(x-h)^2/a

(y-k)/a = (x-h)^2

Take the square root of each side

±sqrt((y-k)/a )= sqrt((x-h)^2)

±sqrt((y-k)/a )= (x-h)

Add h to each side

±sqrt((y-k)/a ) + h= (x-h+h)

±sqrt((y-k)/a ) + h= x

4 0

4 years ago

Read 2 more answers

Four of a sample of 150 computers will be selected and tested. How many ways are there to make this selection? Type a

OleMash [197]

Answer:

20260275

Step-by-step explanation:

the question is same as selecting 4 things from 150 things

= C(150,4). (nCr formula)

=[150×149×148×147]÷[4×3×2×1]

= 49×75×149×37

= 20260275

6 0

4 years ago

An art project has an area of 63.6 square inches. What is the width, in inches, of the project?

miss Akunina [59]

Answer:

Option C . 5.3 in

Step-by-step explanation:

The complete question is

An art project has an area of 63.6 square inches. What is the width, in inches, of the project?

A rectangle is shown divided into 4 smaller rectangles that are related to the size of the edges. The top edge is labeled 10 inches and 2 inches, above the top two rectangles. The top two rectangles are much larger than the bottom two rectangles

Let

x ----> the length of the art project in inches

y ----> the width of the art project in inches

we know that

The area of the rectangular art project is equal to

$A=xy$

we have

$A=63.6\ in^2$

$63.6=xy$ ----> equation A

$x=10+2=12\ in$

substitute the value of x in the equation A

$63.6=(12)y$

solve for y

$y=63.6/12\\y=5.3\ in$

8 0

4 years ago

What is the solution to the equation? (-9x+5)^1/2=(3+4x)1/2

Phoenix [80]

x in (-oo:+oo)

((5-9*x)^1)/2 = ((4*x+3)^1)/2 // - ((4*x+3)^1)/2

((5-9*x)^1)/2-(((4*x+3)^1)/2) = 0

(5-9*x)/2-((4*x+3)/2) = 0

(5-9*x)/2+(-1*(4*x+3))/2 = 0

5-1*(4*x+3)-9*x = 0

2-13*x = 0

(2-13*x)/2 = 0

(2-13*x)/2 = 0 // * 2

2-13*x = 0

2-13*x = 0 // - 2

-13*x = -2 // : -13

x = -2/(-13)

x = 2/13

x = 2/13

4 0

4 years ago