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bekas [8.4K]
3 years ago
11

What OBD-II term applies when all enabling standards for a specific diagnostic trouble code (DTC) are met?

Computers and Technology
1 answer:
mash [69]3 years ago
3 0

Answer:

Option C i.e., Trip criteria is correct

Explanation:

The concept Trip criteria are described that when the allowing requirements for its diagnostic code are reached.

In other words, Trip seems to be a key-on method where all the allowing requirements for such a specific diagnostic display are fulfilled as well as the diagnostic monitoring is powered. It is finished once the ignition switch becomes switched off.

  • Option A and Option B are not correct because they are the engines that come under the performance ignition system and they are not related to the following scenario.
  • Option D is incorrect because it is the type of data mining that is not related to the scenario.
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Answer:

Explanation:

<u>Application Differences:</u>

<u>SRAM</u>

SRAM stands for Static Random Access Memory  DRAM stands for Dynamic Random Access Memory

Faster access is due to the usage of transistors to store single bit of data  

SRAMs are used for cache memories due to faster access time  

<u>DRAM</u>

DRAM stands for Dynamic Random Access Memory

DRAMs are used for main memories due to comparatively slower access time.

DRAMs use capacitor to store bits where each capacitor holds a single bit

<u>Parameter differences</u>  

<u>Speed:</u> SRAMs are faster due to presence of transistors. DRAMs are slower due to presence of capacitors

<u>Size:</u> Due to complexity involved in the internal circuits, SRAMs are smaller in capacity for same size of the chip. DRAMs are larger as compared to SRAMs since their capacity for a given physical size is more.

<u>Cost:</u> SRAMs are costlier and the per bit storage cost is more than that of the DRAMs. DRAMs are cheaper and the per bit storage cost is less than that of the SRAMs

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2 years ago
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aleksley [76]

Answer:

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2 years ago
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I beleive anything to do with manage

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Answer:

Component(CompID, CompName, Description) PK=CompID

Product(ProdID, ProdName, QtyOnHand) PK=ProdID

Supplier(SuppID, SuppName) PK = SuppID

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details of the answer is attached

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Answer:

Answered below

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