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svet-max [94.6K]
3 years ago
7

explain how estimating the quotient helps you place the first digit the quotient of a division problem

Mathematics
2 answers:
kari74 [83]3 years ago
8 0
It gives you an idea of how the quotient will look in your answer
Liula [17]3 years ago
6 0
What are the different ways to divide?
You can use many different strategies to find the answer to a division problem. One strategy is to use repeated subtraction. To find 123 ÷ 36, think: How many groups of 36 are there in 123? Start with 123. Subtract 36 repeatedly. Count how many times you subtracted: 123 − 36 = 87 (1); 87 − 36 = 51 (2); 51 − 36 = 15 (3); 15 < 36. There are 3 groups of 36 in 123 with 15 left over. Therefore, 123 ÷ 36 = 3 R15.
Another strategy is to use what is sometimes called long division. The algorithm for long division is estimate, multiply, subtract, bring down, and repeat as needed. To find 123 ÷ 36, start with the estimate 120 ÷ 40 = 3. Then use this estimate to help you place the first digit in the quotient of the division algorithm.
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Jet001 [13]
I-9 form, hope this helps
3 0
2 years ago
Of 960 pages 384 had an add. What's the probability it contains an add
kramer
384/960
Thus, answer=2/5
4 0
3 years ago
A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2​, drawn from the 11​, will
svet-max [94.6K]

The required probability is \frac{36}{55}

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.  

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, \text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}

Probability for first draw to be non-defective =\frac{11-2}{11}=\frac{9}{11}

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective =\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}

(printers after first slot = 10; total defective printers = 2)

Then, total probability =\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}

7 0
3 years ago
A little help please
DaniilM [7]

Answer:

x = 30

Step-by-step explanation:

by solving ;

  • 18 / x = 6 / 10
  • 1 / x = 6 / ( 18 × 10 )
  • 1 / x = 6 / 180
  • 1 / x = 1 / 30
  • x = 30

4 0
3 years ago
What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L container at 25.0°C?
drek231 [11]

Answer:

1.2218 atm

Step-by-step explanation:

From ideal gas formula,

PV=nRT

Where n= number of moles

V= volume

T= temperature=25.0°C

= (273 + 25) = 298 K

R= gas constant = 0.082 l atm /K mol.

Making P subject of formula we have

P= [nRT] /V

Then substitute the values we have

P= [0.5 x 0.082 x 298] / 10

P= 1.2218 atm

6 0
3 years ago
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