Evaluate 18-T, if T=4
2 answers:
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The confidence interval for the difference p1 - p2 of the population proportion is (0.063, 0.329)
<h3>How to determine the confidence interval?</h3>The given parameters are:
n₁ = 93; n₂ = 80
p₁ = 0.814; p₂ = 0.618
The critical value at 95% confidence interval is
z = ±1.96
So, we have:
Substitute known values in the above equation
Evaluate
This gives
CI = 0.196 ± 0.133
Expand
CI = (0.196 - 0.133, 0.196 + 0.133)
Evaluate
CI = (0.063, 0.329)
Hence, the confidence interval is (0.063, 0.329)
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