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3 years ago

Simplify this expression leaving your answer in index form

Mathematics

1 answer:

kenny6666 [7]3 years ago

3 0

Answer:

solution is 9a^16

Step-by-step explanation:

(6)^2= 36

(a^5)^2= a^25

36a^25/(9a^9)

(36/9)= 4

(a^25)/(a^9)= a^(25-9)= a^16

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Changle. Show all work. Round each length to the nearest tenth and each angle to the

Sedaia [141]

Answer:

Part 1) $BC=12.2\ units$

Part 2) $m\angle A=55^o$

Part 3) $m\angle C=35^o$

Step-by-step explanation:

Part 1) Find AC

we know that

In the right triangle ABC of the figure

Applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=7^2+10^2$

$AC^2=149\\AC=12.2\ units$

Part 2) Find the measure of angle A

we know that

In the right triangle ABC

$tan(A)=\frac{BC}{AB}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{10}{7}$

using a calculator

$m\angle A=tan^{-1}(\frac{10}{7})=55^o$

Part 3) Find the measure of angle C

we know that

In the right triangle ABC

$m\angle A+m\angle C=90^o$ ----> by complementary angles

substitute the given value

$55^o+m\angle C=90^o$

$m\angle C=90^o-55^o=35^o$

8 0

3 years ago

If g(x) = -2x - 2, find g(-2x).

USPshnik [31]

Answer:

Step-by-step explanation:

You would replace the x with -2x so you would end up with -2×-2 and that is 4 then minus 2 is 2.

7 0

3 years ago

Joe is hiking a trail that is 30 miles long. after several days, he is two times as far from the beginning of the trail as he is

lora16 [44]

In order to answer this question let's suppose,
Joe is x miles from the beginning and y miles from the end. These assumptions are necessary to answer further:

Now,
x=2y
x+y=30
plugging in x=2y in the above equation
2y+y=30
3y=30
y=10

Hence, according to our calculations, Joe has to hike 10 miles further

5 0

3 years ago

Rita started the day with r apps. then she deleted 5 apps and still had twice as many apps as Cora has. write an equation that r

lianna [129]

Answer:

Rita had r apps as the start of the day

After she deleted 5 apps,

equation for apps of cora = (r-5)

Equation for apps of Rita = 2 (r-5)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

Simplify this expression leaving your answer in index form​

Simplify this expression leaving your answer in index form