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3 years ago

Simplify this expression leaving your answer in index form

Mathematics

1 answer:

kenny6666 [7]3 years ago

3 0

Answer:

solution is 9a^16

Step-by-step explanation:

(6)^2= 36

(a^5)^2= a^25

36a^25/(9a^9)

(36/9)= 4

(a^25)/(a^9)= a^(25-9)= a^16

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3 years ago

Need help asap giving 20 points for right answer!!

andrey2020 [161]

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2 years ago

Please help!!!!!!!!!!!

Assoli18 [71]

Let's take this problem step by step:

To find the ordered pair of the system:

⇒ must set both equations equal to each other

⇒ and solve for 'x'

Let's solve:

$x^2-2x+3=-2x+19\\x^2-2x+2x+3-19=0\\x^2-16=0\\(x+4)(x-4)=0$

Let's find the x-values:

$(x-4)=0\\x=4\\\\(x+4)=0\\x=-4$

Let's find f(x)'s value for each 'x':

$x=4\\f(4)=-2(4)+19=-8+19=11\\\\x=-4\\f(-4)=-2(-4)+19=8+19=27$

Answer: (4, 11), (-4,27)

Hope that helps!

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1 year ago

If you are accelerating at 10 m/s^2, describe how fast the velocity is changing

Svetlanka [38]

Answer:

:( couldn't find the answer, but I need more information such as what the initial velocity was... Hope someone gives a good answer!

Have a great day! I'm sorry I couldn't be any help, you could delete this if you want :')

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3 years ago

Jack travels to work on the Eastern Freeway. He notices that the difference in time between if he drives 5 mph below the speed l

Misha Larkins [42]

Let's denote s as the speed limit. To find the total time it takes for Jack to drive given the speed, we just divide the total number of miles he covered (10 miles) by the speed he's traveling at.

Accounting for the given of the problem, we'll have the following equation:
$\frac{10}{s-15} - \frac{10}{s-5}= \frac{1}{30}$ (from the fact that the difference between the time it takes to drive five miles below the speed limit versus 15 miles below is 2 mins or $\frac{1}{30}$ hours.)

Since we only have one unknown variable, we can freely solve for s:
$\frac{10}{s-15} - \frac{10}{s-5}= \frac{1}{30}$
$\frac{10(s-5)-10(s-15)}{(s-15)(s-5)}= \frac{1}{30}$
$\frac{10s-50-10s+150}{s^{2}-5s-15s+75}= \frac{1}{30}$
$\frac{100}{s^{2}-20s+75}= \frac{1}{30}$
$3000=s^{2}-20s+75$
$0=s^{2}-20s-2925$
$s_{1}=65$
$s_{2}=-45$ (we ignore the negative value since there is no negative speed.)

ANSWER: The speed limit of the freeway is 65 mph.

3 0

3 years ago

Read 2 more answers

Simplify this expression leaving your answer in index form​

Simplify this expression leaving your answer in index form