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Lyrx [107]
3 years ago
8

A figure is a cylinder with a radius of 6 inches and a height of 10 inches. On top of the cylinder is a hemisphere with a radius

of 6 inches. Find the volume.
A) 102π in3
B) 348π in3
C) 504π in3
D) 888π in3
Mathematics
2 answers:
Oksana_A [137]3 years ago
6 0
C, 504\pi in3
IRINA_888 [86]3 years ago
3 0

Answer:

C. 504\pi\text{ inches}^3

Step-by-step explanation:

We have been given that a figure is a cylinder with a radius of 6 inches and a height of 10 inches. On top of the cylinder is a hemisphere with a radius of 6 inches.

The volume of our given figure will be equal to volume of cylinder plus volume of hemisphere.

\text{Volume of cylinder}=\pi r^2h, where,

r = Radius of cylinder,

h = height cylinder.

Upon substituting our given values in above formula we will get,

\text{Volume of cylinder}=\pi\text{(6 inch)}^2*\text{ 10 inches}

\text{Volume of cylinder}=\pi*36\text{ inch}^2*\text{ 10 inches}

\text{Volume of cylinder}=360\pi\text{ inch}3

Now let us find the volume oh hemisphere part of our figure using formula,

\text{Volume of hemisphere}=\frac{2}{3}\pi r^3

\text{Volume of hemisphere}=\frac{2}{3}\pi*\text{ 6 inches}^3

\text{Volume of hemisphere}=\frac{2}{3}\pi*216\text{ inches}^3

\text{Volume of hemisphere}=\pi*2*72\text{ inches}^3

\text{Volume of hemisphere}=144\pi\text{ inches}^3

\text{Volume of the figure}=\text{Volume of cylinder + Volume of hemisphere}

\text{Volume of the figure}=360\pi\text{ inch}3+144\pi\text{ inches}^3

\text{Volume of the figure}=504\pi\text{ inches}^3

Therefore, the volume of our given figure is 504\pi\text{ inches}^3 and option C is the correct choice.

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OLga [1]

Answer:

(x - 5)² + (y + 3)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (5, - 3) and r = 4, thus

(x - 5)² + (y - (- 3))² = 4², that is

(x - 5)² + (y + 3)² = 16 ← equation of circle

4 0
3 years ago
What is the Volume of the square pyramid? (Round to the nearest tenth as needed)
goldenfox [79]

Answer:

5229 mm³

Step-by-step explanation:

Volume of square pyramid

\sf \boxed{Volume \ of \ the \ square \ pyramid = \dfrac{1}{3}*b^2*H}

      b = base length = 25 mm

       H = height

         We have to find 'H' using Pythagorean theorem,

              slant height (hypotenuse) = 28 mm

                                                  leg₁ = base length  ÷ 2 = 25÷2 = 12.5

                                                  leg₂ = H

     H² + (12.5)² = 28²

                  H²   = 784 - 156.25

                         = 627.75

                   \sf H = \sqrt{627.75}

                 H = 25.01 mm

          \sf  \text{Volume of square pyramid =$\dfrac{1}{3}*25*25*25.1$ }

                                                     = 5229 mm³

                                                     

       

\sf \boxed{\text{Volume of square pyramid = \dfrac{1}{3}*25*25*28}}

3 0
2 years ago
Read 2 more answers
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Hatshy [7]

Answer:

430 + 16h

Step-by-step explanation:

They are staying for a week ($430)

They are renting both a kayak ($7 per hour) and paddle board ($9 per hour), without defining the amount of hours. Create a variable, for example H for hours.

To create the expression, take the $430, the $7 per hour and $9 per hour, or 430 + 16h.

5 0
2 years ago
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attashe74 [19]

Respuesta:

25 cm²

Explicación paso a paso:

El área A de un rombo tiene:

A = pq / 2

Donde pyq son las diagonales

Tomando p como la diagonal más grande = 10 cm

Diagonal más pequeña, q = 1/2 * 10 = 5cm

Por lo tanto, el área del rombo es:

A = (10 * 5) / 2

A = 50/2

A = 25 cm²

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Fynjy0 [20]

Answer:

Imao 5

Step-by-step explanation:

just divide

5 0
3 years ago
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