Well for the first one you have to subtract 3 on both sides so that would make the equation x > -8 (because a negative subtracting a positive is basically a negative plus negative) and so your equations done. For the second one you divide both ides by -4 so your equation would be x < 4 (the sign would be less then or qual to because you divided by a negative)
In the 
plane, we have 
everywhere. So in the equation of the sphere, we have
which is a circle centered at (2, -10, 0) of radius 4.
In the 
plane, we have 
, which gives
But any squared real quantity is positive, so there is no intersection between the sphere and this plane.
In the 
plane, 
, so
which is a circle centered at (0, -10, 3) of radius 
.
Answer:
These are the answers for question 3 only.
Step-by-step explanation:
3)
a. 3 <u>></u> -3
b. 12 <u><</u> 24
c. -12 <u>></u> -24
d. 5 <u>></u> -(-5) - (I'm not sure about this one)
e. 7.2 <u>></u> 7
f. -7.2 <u><</u> -7
g. -1.5 <u>=</u> -3/2
h. -4/5 <u>></u> -5/4
i. -3/5 <u>=</u> -6/10
j. -2/3 <u><</u> 1/3
972. Keep in mind the ratio of square feet to square inches is 144:1 as opposed to 12:1
