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3 years ago

Please help I’ll give you Brainliest

Mathematics

2 answers:

vladimir2022 [97]3 years ago

6 0

Answer:

30 degrees/ An Acute Angle (If I'm wrong please comment on my answer)

Step-by-step explanation:

Alina [70]3 years ago

4 0

180 i believe it looks like it’d be supplementary and plus it is a straight line

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Please I need help on this ASAP

KATRIN_1 [288]

Answer:

$\frac{1}{256}$

Step-by-step explanation:

$\frac{1}{16} \times \frac{1}{16} = \frac{1}{256}$

there are 16 classmates in total including bess and caroline. and there chances as one person is 1 out of those 16 classmates.

6 0

2 years ago

Paul's

dlinn [17]

Step-by-step explanation:

I hope you have a good day

5 0

3 years ago

Read 2 more answers

The sum of the measures of angle A and angle B is 180 degrees. The measure of angle A is (4x + 12) The measure of angle B is 60

BARSIC [14]

Answer:

Rolf prepares four solutions using different solutes as shown in the table be❤️low.

Which solution is unsaturated?

Solution A

Solution B

Solution C

Solution D

Step-by-step explanation:

5 0

2 years ago

Find the derivative.

Aleksandr [31]

Answer:

Using either method, we obtain: $t^\frac{3}{8}$

Step-by-step explanation:

a) By evaluating the integral:

$\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du$

The integral itself can be evaluated by writing the root and exponent of the variable u as: $\sqrt[8]{u^3} =u^{\frac{3}{8}$

Then, an antiderivative of this is: $\frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}$

which evaluated between the limits of integration gives:

$\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}$

and now the derivative of this expression with respect to "t" is:

$\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}$

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

$g(x)=\int\limits^x_a {f(t)} \, dt$

is continuous on [a,b], differentiable on (a,b) and $g'(x)=f(x)$

Since this this function $u^{\frac{3}{8}$ is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

$\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}$

5 0

3 years ago

Choose all the functions that give the sequence:

TEA [102]

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Further explanation:

We will put n=1,2,3,4,5 to find which functions give the given sequence

f(n) = 2n − 1

Putting values of n

$f(1)=2(1)-1=2-1=1\\f(2)=2(2)-1=4-1=3\\f(3)=2(3)-1=6-1=5$

This function doesn't generate the given sequence

f(n) = 2n + 1

Putting values of n

$f(1)=2(1)+1=2+1=3\\f(2)=2(2)+1=4+1=5\\f(3)=2(3)+1=6+1=7\\f(4)=2(4)+1=8+1=9\\f(5)=2(5)+1=10+1=11$

This function generates the given sequence.

f(n) = 2(n − 1) − 3

Putting values of n

$f(1) = 2(1 -1) -3=2(0)-3=0-3=-3\\f(2) = 2(2 -1) -3=2(1)-3=2-3=-1\\f(3) = 2(3-1) -3=2(2)-3=4-3=1$

This function doesn't generate the given sequence

f(n) = 2(n − 1) + 3

Putting values of n

$f(1) = 2(1 - 1) + 3=2(0)+3=0+3=3\\f(2) = 2(2 - 1) + 3=2(1)+3=2+3=5\\f(3) = 2(3 - 1) + 3=2(2)+3=4+3=7\\f(4) = 2(4 - 1) + 3=2(3)+3=6+3=9$

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Keywords: Functions, Sequence

Learn more about functions at:

#LearnwithBrainly

8 0

3 years ago