All categories

3 years ago

Please help I’ll give you Brainliest

Mathematics

2 answers:

vladimir2022 [97]3 years ago

6 0

Answer:

30 degrees/ An Acute Angle (If I'm wrong please comment on my answer)

Step-by-step explanation:

Alina [70]3 years ago

4 0

180 i believe it looks like it’d be supplementary and plus it is a straight line

You might be interested in

PLEASE HELP! WILL MARK BRAINLIEST

Veseljchak [2.6K]

The value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.

<h3>How to determine the dimensions?</h3>

The given parameters are:

Base = 5(x+3)

Height = 2(x+9)

Perimeter = 108

The perimeter of a rectangle is

P = 2 *(Base + Height)

So, we have:

2 *(5(x + 3) + 2(x + 9)) = 108

Divide both sides by 2

5(x + 3) + 2(x + 9) = 54

Open the brackets

5x + 15 + 2x + 18 = 54

Evaluate the like terms

7x = 21

Divide by 7

x = 3

Substitute x = 3 in Base = 5(x+3) and Height = 2(x+9)

Base = 5(3+3) = 30

Height = 2(3+9) = 24

Hence, the value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.

Read more about perimeter at:

brainly.com/question/24571594

#SPJ1

5 0

1 year ago

Blanca's house is assessed at $149,000 and her property tax rate is 2.3%. How much is her annual property taxes?

mrs_skeptik [129]

$3,427 because you take 149000 and multiply by .023 for 2.3%.

5 0

3 years ago

Read 2 more answers

Find all solutions of the equation: 2cos^2x-cosx=1

Art [367]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166243

——————————

Solve the trigonometric equation:

$\mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}$

Make a substitution:

$\mathsf{cos\,x=t\qquad (-1\le t\le 1)}$

and the equation becomes

$\mathsf{2t^2-t-1=0}$

Rewrite conveniently – t as + t – 2t, and then factor the left-hand side by grouping:

$\mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}$

Factor out 2t + 1:

$\mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}$

Substitute back for t = cos x:

$\begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}$

Therefore,

$\begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}$

where k is an integer.

Solution set:

$\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}$

I hope this helps. =)

3 0

3 years ago

Does someone know the answer

BlackZzzverrR [31]

The answer to your question is c

6 0

3 years ago

1. suppose you purchased a new car for

Xelga [282]

If the value of the car decreases by 8% every year it would take 13 years for the car to be worth
$10000.00.

8 0

2 years ago