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3 years ago

How do u solve to get x?

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

4 0

Step-by-step explanation:

2^(2x) - 5(2^x) = -4

(2^x)^2 - 5(2^x) = -4

Substitute 2^x = z --> x = ln(z)/ln(2)

z^2 - 5z = -4

z^2 - 5z + 4 = 0

(z - 1)(z - 4) = 0

z = 1 --> x = ln(1)/ln(2) = 0

z = 4 --> x = ln(4)/ln(2) = 2

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a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect

PolarNik [594]

Number of dimes were 81 and number of quarters were 47

Solution:

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that There are 128 coins in all

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

Also given that collection of dimes and quarters is worth $19.85

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

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Let us solve eqn 1 and eqn 2

From eqn 1,

d = 128 - q -------- eqn 3

Substitute eqn 3 in eqn 2

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

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d = 128 - q

d = 128 - 47

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3 years ago

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Answer:

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