All categories

4 years ago

Subtract -9x^2+2x+5from 8x^2+8x +8.

Mathematics

1 answer:

pav-90 [236]4 years ago

8 0

So 8x^2+8x+8-(-9x^2+2x+5) is going to be
8x^2+9x^2+8x-2x+8-5
Giving you

17x^2+6x+3

You might be interested in

On the way home from school, Ross wears his 20-pound backpack and carries his 7-ounce lunchbox. How many ounces does he carry in

Angelina_Jolie [31]

Answer:327

Step-by-step explanation:

20 pounds is 320 ounces and the lunch box plus that is 327 ounces

8 0

4 years ago

what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible

zheka24 [161]

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

$\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$

$=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}$

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0

3 years ago

Can you guys help please im so confused

marissa [1.9K]

Answer:

a) see below

b) 40x20 meters

Step-by-step explanation:

Write down what you know:

- The area of the enclosure is length*width, so

$A = x \cdot y$

- The length of the fencing is 80 meters, so

$2y + x = 80$

Now we have to combine these two equations above, and get rid of y in the process.

First rewrite the second as:

$y = 40 - \frac12 x$

Then substitute for y in the first:

$A = x (40 - \frac12 x) = 40x - \frac12x^2$

b) To maximize A, find the zero of the first derivative:

$A'(x) = 40 - x = 0 \implies x=40$

So y = (80-40)/2 = 20 meters.

8 0

3 years ago

a crane lifts a 450 kg concrete to the top of a 50 m building in 5 s. assuming g=10 m/s² calculate a) the potential energy of th

Juliette [100K]

Answer:

Step-by-step explanation:

The work done changes the potential energy

ΔPE = mgΔh = 450(10)(50) = 225,000 = 225 kJ

power is the rate of doing work

P = 225000/5 = 45000 W = 45 kW

5 0

3 years ago

Verify identity list steps. Cot(t)(1-cos^2(t))=cos(t)sin(t)

storchak [24]

Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)

You should already know this:

$\huge{Cot(t) = \frac{1}{tan(t)} = \frac{1}{\frac{sin(t)}{cos(t)}} = 1\div \frac{sin(t)}{cos(t)} = 1\times \frac{cos(t)}{sin(t)}=\boxed{\frac{cos(t)}{sin(t)}}$

You should also know this:

$sin^2(t) + cos^2(t) = 1\\\\\boxed{sin^2(t)} = 1 - cos^2(t)$

So plugging in both of those into our identity, we get:

$\frac{cos(t)}{sin(t)}\cdot sin^2(t) = cos(t)\cdot sin(t)$

Simplify the denominator on the LHS (Left Hand Side)

We get:

$cos(t) \cdot sin(t) = cos(t) \cdot sin(t)$

LHS = RHS

Therefore, identity is verified.

4 0

3 years ago