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Alborosie
3 years ago
5

Build the greatest number less than 700 that has 9 in the tens place and different digits in each of the other places

Mathematics
2 answers:
suter [353]3 years ago
8 0
I think the greatest number less than 700 with 9 in the tens place and different digits in each of the other places is 698.
I chose 6 to be in the one of hundreds place because it is the greatest number that is less than 7 in the hundreds place. I also chose 8 to be in the ones place because it is different from 6 and 9 and the greatest number in the ones place that is not 9.
patriot [66]3 years ago
7 0
699, because it has 9 in the tens place and 9 in the ones would be the greatest number there, and 6 in the tens, because it has to be less than 700.
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Hank used 410 stamps. There are 60 stamps in every 3 rolls. How many rolls did Hank use?
Sveta_85 [38]

Answer:

20 rolls

Step-by-step explanation:

there is 20 in each roll 410/20 is 20.8.

7 0
3 years ago
Solve and explain please
Ann [662]

Answer:

j= -9, -2

Step-by-step explanation:

(j+9)(j+2)

j=-9, -2

3 0
3 years ago
Read 2 more answers
What is the equation of a line that is perpendicular to -x + 2y =4 and passes through the point (-2, 1)
Trava [24]

Answer:

y = -2x - 3

Step-by-step explanation:

-solve for y: y = 1/2x + 2

-perpendicular equals opposite slope: -2

-plug in the point: (1) = -2(-2) + b

                               1 = 4 + b

                                b = -3

put it all together: y = -2x - 3

8 0
3 years ago
Solve for x: 3|x-3| 2=14<br> a. No solution<br> b. x=-1,x=8.3<br> c. x=0,x=7<br> d. x=-1,x=7
VMariaS [17]
I am looking  on the answers, and there is only one case, when a or b or c or d pass:   3|x-3| + 2 = 14.  So I assume, that before two is plus. Then:

3|x-3|+2=14    |minus 2
3|x-3|=12        |divide 3
|x-3|=4 

From absolute value definition you've got two ways:

x-3=4     or     x-3=-4
x=7        or     x=-1

And  answer d) passes

3 0
3 years ago
Graph the image of this figure after a dilation with a scale factor of 1/3 centered at the origin.
posledela

Answer:

see attached diagram

Step-by-step explanation:

A dilation with a scale factor of \dfrac{1}{3} centered at the origin has a rule:

(x,y)\mapsto\left(\dfrac{x}{3},\dfrac{y}{3}\right).

Then the image of the triangle ABC is triangle DEF(see attached diagram) with coordinates

  • D\left(\dfrac{-3}{3},\dfrac{3}{3}\right)\Rightarrow D(-1,1);
  • E\left(\dfrac{3}{3},\dfrac{9}{3}\right)\Rightarrow E(1,3);
  • F\left(\dfrac{6}{3},\dfrac{6}{3}\right)\Rightarrow F(2,2).

3 0
3 years ago
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