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3 years ago

F(x) = − 1 2 x for x = –6

Mathematics

2 answers:

Nesterboy [21]3 years ago

8 0

Answer:

Your an idiot and i oop hahahahah thats what u did on my question. YOUR AN IDIOT UR A IDIOT U SUCK.

Step-by-step explanation:

svetoff [14.1K]3 years ago

3 0

Here is the explanation

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Fiona has $18 to spend. She spent $4.25, including tax, to buy a notebook. She needs to save $9.75, but she wants to buy a snack

Irina18 [472]

1. $18-4,25=13,75 \\ 13,75-9,75=4 \\ 0,50x \leq 4$ <u />⇔ $x= \frac{4}{0,50}$ ⇔ $x= 8$
R: She can buy 8 crackers

2. Amy used 13%
Dan used 0,14*100 = 14%
Mike used 0,5*100 = 50%
R: Mike used the greatest amount of milk.

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3 years ago

Can someone answer this problem please

TEA [102]

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4 0

3 years ago

HELP ASAP FOR LOTS OF POINTS AND BRAAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

WARRIOR [948]

Answer:

Step-by-step explanation:

Hope this helped!

7 0

3 years ago

Someone help please

Alla [95]

Answer: Choice A

$\tan(\alpha)*\cot^2(\alpha)\\\\$

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Explanation:

Recall that $\tan(x) = \frac{\sin(x)}{\cos(x)}$ and $\cot(x) = \frac{\cos(x)}{\sin(x)}$ . The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

$\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\$

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why $\tan(\alpha)*\cot^2(\alpha)\\\\$ is identical to $\frac{\cos(\alpha)}{\sin(\alpha)}\\\\$

Therefore, $\tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\$ is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that $\tan(\alpha)*\cot^2(\alpha)\\\\$ is the same as $\frac{\cos(\alpha)}{\sin(\alpha)}\\\\$ by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

6 0

2 years ago

Sam is using the expression M/8n in class. What is the value of this expression when m = 4 and n = 1/2

vichka [17]

Answer:

Step-by-step explanation:

m/8n > 4/8(1/2) ( since its 1/2 all you need to do is change the fraction to whole number which is 1/2 = 0.5)

The given will become 4/4 then simplest form is 1

4 0

2 years ago