The sum of two numbers is 18. One number is 2 more that for times the other. Find the numbers.
1 answer:
Hi there!
Let the first number be represented by X.
The second number (which is 2 more than four times the other), can be represented by 4X + 2.
We can now find the sum of this expression.
X + 4X + 2
Collect terms
5X + 2
The sum of the numbers is 18. Therefore we can set up the following equation.
5X + 2 = 18
Subtract 2.
5X = 16
Divide both sides by 5.
X = 16/5 = 3 1/5.
Therefore, the first number is 3 1/5. To find the second number we must plug in X = 3 1/5 into the expression 4X + 2
4 * (3 1/5) + 2 = 12 4/5 + 2 = 14 4/5
The two numbers are
~ Hope this helps you!
Let the first number be represented by X.
The second number (which is 2 more than four times the other), can be represented by 4X + 2.
We can now find the sum of this expression.
X + 4X + 2
Collect terms
5X + 2
The sum of the numbers is 18. Therefore we can set up the following equation.
5X + 2 = 18
Subtract 2.
5X = 16
Divide both sides by 5.
X = 16/5 = 3 1/5.
Therefore, the first number is 3 1/5. To find the second number we must plug in X = 3 1/5 into the expression 4X + 2
4 * (3 1/5) + 2 = 12 4/5 + 2 = 14 4/5
The two numbers are
~ Hope this helps you!
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Answer:
Step-by-step explanation:
a) Pythagorean theorem,
altitude² + base² = hypotenuse²
h² + (w² - 1)² = (w² + 1)²
h² = (w² + 1)² - (w² - 1)²
{Compare with (a + b)² - (a -b)² = 4ab where a =w² & b = 1}
h² = 4*w²*1
h² = 4w²
b) Area of triangle =
c) w =2
Area of triangle = 3w = 3*2 = 6