The sum of two numbers is 18. One number is 2 more that for times the other. Find the numbers.
1 answer:
Hi there!
Let the first number be represented by X.
The second number (which is 2 more than four times the other), can be represented by 4X + 2.
We can now find the sum of this expression.
X + 4X + 2
Collect terms
5X + 2
The sum of the numbers is 18. Therefore we can set up the following equation.
5X + 2 = 18
Subtract 2.
5X = 16
Divide both sides by 5.
X = 16/5 = 3 1/5.
Therefore, the first number is 3 1/5. To find the second number we must plug in X = 3 1/5 into the expression 4X + 2
4 * (3 1/5) + 2 = 12 4/5 + 2 = 14 4/5
The two numbers are
~ Hope this helps you!
Let the first number be represented by X.
The second number (which is 2 more than four times the other), can be represented by 4X + 2.
We can now find the sum of this expression.
X + 4X + 2
Collect terms
5X + 2
The sum of the numbers is 18. Therefore we can set up the following equation.
5X + 2 = 18
Subtract 2.
5X = 16
Divide both sides by 5.
X = 16/5 = 3 1/5.
Therefore, the first number is 3 1/5. To find the second number we must plug in X = 3 1/5 into the expression 4X + 2
4 * (3 1/5) + 2 = 12 4/5 + 2 = 14 4/5
The two numbers are
~ Hope this helps you!
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, the are of the rhombus is
So, in your case, the area is
The other options are wrong because:
- option A doens't divide by 2, thus getting twice the area of the rhombus
- option B summed the diagonals instead of multiplying them
- option D took the difference of the diagonals.