First, find the area of lot A.
To find the area, multiply the length by the width.
33*42=1,386
Now, subtract the area of lot a from the total area. This will give us the area of lot b.
1,848-1,386=462
The area of lot b is 462 square feet.
Finally, divide the area of lot b (462) by its length to find the width. Since they both share a side, we know that it’s length is 42 feet.
462/42=11
Lot b is 11 feet wide.
Hope this helps!
Answer:
The length of one side is 13 feet.
Step-by-step explanation:
To start, a square is 4 sides that are equal in length. This means that when you have a problem like this, you need to set the equations equal to each other like:
In order to solve a problem like this, with the same variables on different sides, start by subtracting the smaller variable from both sides. In this case, you would be subtracting 2x from both sides, which would leave us with:
After that, you solve it like a normal one-step equation. Add 11 to both sides.
Now, divide both sides by 4 and you will know how much 
is worth.
Now that we know how much is worth, we can plug that into either of the equations given to us. It doesn't matter which since they are equal to each other.
That would give us 13.
10 3/5=10.6
10.6+12.5=23.1
35.0-23.1=11.9
It is 11.9 miles from Chester to Durbin.
The practical domain is all real numbers from 4 to 9, inclusive.
The practical range is all real numbers from 49.6 to 111.6, inclusive.
These are the correct options.
Explanation:
Given function is f(t) = 12.4t
Let us assume that Nate works 'x' hours so 4<x<9
And multiplying the hours with his earnings we get the range.
4*12.40=49.6 and 9*12.40=111.6. Let the amount earned be represented by y
Hence, domain can be represented as 4<x<9 and range can be represented as 49.6 < y < 111.6
30. is just asking where the two equations graphed intersect each other...
x = -3 and x = 1 for intersections.
