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allsm [11]
3 years ago
12

What is the factorization of the trinomial below -x^2+2x+48

Mathematics
2 answers:
Marrrta [24]3 years ago
8 0

Answer:

-(x+6)(x-8)

Step-by-step explanation:

-x²+2x+48

take out the negative

-(x²-2x-48)

factors of 48 with a difference of -2

-8, 6

-(x+6)(x-8)

irina1246 [14]3 years ago
8 0

Answer:

-(x-8)(x+6)

Step-by-step explanation:

The given trinomial is

-x^2+2x+48

By comparing to ax^2+bx+c, we a=-1,b=2,c=48.

ac=-1\times 48=-48

Two factors of -48 that adds up to 2 are 8,-6.

We split the middle term to obtain;

-x^2+8x-6x+48

We now factor by grouping;

-x(x-8)-6(x-8)

We factor further to obtain;

(x-8)(-x-6)

-(x-8)(x+6)

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