11/4% = (11/4)/100 = 11/400 = 0.0275;
1/4 = 0.2500;
1/80 = 0.0125;
We observe that 0.0125 < 0.0275 and 0.0114 < 0.0275 and 0.2500 > 0.0275 and 0.12500 > 0.0275;
The answers are c. and d.
Answer:
AM = 6
Step-by-step explanation:
Using the property of a parallelogram
• The diagonals bisect each other
MO is a diagonal, hence
AM = AO = 6
<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
60 out of 100 scores are passing scores, hence 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
A similar problem is given at brainly.com/question/16807970
Answer:
30 cm
Step-by-step explanation:
Sorry if im wrong
Answer:
-3
Step-by-step explanation: