Answer: B. (-2, 3)
Step-by-step explanation: The two lines have the same solution where both lines intersect. So, if you look at the point on the graph where the two lines intersect, and count the tick marks on the number lines, the point is clearly located at (-2, 3).
Josie does bc If ur looking for the unit rate u only need to find it for sherry. you will get 50 miles per hour. if that's how u mean then Josie goes faster. hope this helps
Answer:
the answer for question 2 is (D)
Answer:
love your family
Step-by-step explanation:
<h3>
Answer: Always</h3>
Proof:
Let
- A = some rational number
- B = some irrational number
- C = some rational number (that isn't necessarily equal to A)
We'll show that a contradiction happens if we tried to say A+B = C.
In other words, we'll show a contradiction happens for the form rational+irrational = rational.
Because A and C are rational, we can say
A = p/q
C = r/s
where p,q,r,s are integers. The q and s in the denominators cannot be zero.
So,
A+B = C
B = C - A
B = (r/s) - (p/q)
B = (qr/qs) - (ps/qs)
B = (qr-ps)/(qs)
B = (some integer)/(some other integer)
B = some rational number
But wait, we stated that B was irrational. The term "irrational" literally means "not rational". Irrational numbers cannot be written into fraction form of two integers. This is a contradiction and shows that A+B = C is never possible if A,C are rational while B is irrational.
This must lead to the conclusion that A+B must always be irrational if A is rational and B is irrational.
The template is this
rational + irrational = irrational
rational + rational = rational
