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3 years ago

.write the number in .000101 in scientific notation

Mathematics

1 answer:

schepotkina [342]3 years ago

6 0

Answer:

1.01*10^-4

Step-by-step explanation:

first nonzero digit is 4 places to the right of the decimal point

.000<u>1</u>01

move decimal point 4 places to the right

1.01

multiply by 10^-4 since it was 4 places to the right

1.01*10^-4

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Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

5 0

3 years ago

PLEASEEEEE SURELY SOMEBODY OUT THERE MUST KNOW HOW TO DO THIS FREAKIN HARDD COMPLICATED MATHHH PLSSS HELPPP MEEEEEEEEEEEEEEEEEEE

FromTheMoon [43]

Question 5 is (-3,4)

4 0

2 years ago

A jar contains 6 yellow marbles, 4 black marbles, and 2 purple marbles. Two marbles are picked at random, without replacement. W

ludmilkaskok [199]

Answer:

The probability of selecting both yellow is 5/22.

Step-by-step explanation:

Given the number of yellow marbles = 6

Black marbles = 4

Purple marble = 2

Now find the total number of marbles in the jar.

Thus total marbles = Yellow marbles + Black marbles + Purples marble

Now insert the values in the above formula.

Total marbles = 6 + 4 + 2

Total marbles = 12

The probability of 2 yellow marble:

$= \frac{6}{12} \times \frac{5}{11} \\= \frac{5}{22}$

Thus, the probability of selecting both yellow is 5/22.

3 0

3 years ago

. Choose the correct means and standard deviations for the Sincere and Insincere conditions. Make sure to round to two decimal p

tensa zangetsu [6.8K]

Answer:

C. The rudely disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the politely disagrees condition has a mean of 3.82 and standard deviation of 0.97

Step-by-step explanation:

The given data is

x` Std. Dev

R. disagrees 4.16 0.854

P. disagrees 3.82 0.967

From this data we see that the R. disagrees has a mean of 4.16 and standard deviation of 0.854

while

the P. disagrees has a mean of 3.82 and standard deviation of 0.967.

Same figures are given only in option C because

Rounding 0.854 gives 0.85

Rounding 0.967 gives 0.97

So only option C is the best choice.

C. The R. Disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the P. Disagrees condition has a mean of 3.82 and standard deviation of 0.97

8 0

3 years ago

List 3 values that would make this inequality true 43 < y -30

prohojiy [21]

43 < y - 30
add 30 to both sides
73 < y

y can be anything that is greater than 73
so it could be...
101, 74, 90, 75, 980767, 5674, etc.

Hope this helps!

4 0

3 years ago