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4 years ago

the perimeter of a rectangle field is 340 yd. the length is 30 yd longer than the width. find the dimensions

Mathematics

2 answers:

zvonat [6]4 years ago

8 0

Lets assume:

Width=x

Length=x+30

2x+2(x+30)=340

2x+2x+60=340

4x+60=340

4x=280

x=70

Plugging x in:

Width=70

Length=100

Ivahew [28]4 years ago

4 0

Let l: length, w=width
2(l+w)=340, l=w+30
l+w=170
w+30+w=170
2w=140
w=70 yd.
l=70+30=100 yd
So the length of the rectangle field is 100 yd. and the width of the rectangle field is 70 yd. Hope it help!

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is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ $x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and $y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

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* The coordinates of point A are (-11 , 2)

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