Answer:
GH=15
Step-by-step explanation:
HK= FK/2= 16/2= 8
Using pythagoras theorem in triangle GHK,
GH²= GK²-HK²
= 17²-8²
= 225
GH= √225
=15
Answer:
Step-by-step explanation:
given,
a) √x + 6 = 4
to solve the above equation subtract both side with 6
√x + 6 - 6 = 4 - 6
√x = -2
squaring both side
(√x)² = (-2)²
x = 4
a) ∛x + 6 = 4
to solve the above equation subtract both side with 6
∛x + 6 - 6 = 4 - 6
∛x = -2
cubing both side
(√x)³ = (-2)³
x = -8
9514 1404 393
Answer:
- 13 ft
- (a) 1 second; (b) t = 0, t = 1/2
Step-by-step explanation:
<h3>1. </h3>
Let w represent the length of the wire. Then the height of attachment is (w-1). The Pythagorean theorem tells us a relevant relation is ...
5² +(w -1)² = w²
w² -2w +26 = w² . . . . . . . eliminate parentheses, collect terms
26 = 2w . . . . . . . . . . . . add 2w
13 = w . . . . . . . . . . . . divide by 2
The length of the wire is 13 feet.
__
<h3>2. </h3>
(a) When h = 0, the equation is ...
0 = -16t^2 +8t +8
Dividing by -8 puts this into standard form:
2t^2 -t -1 = 0
Factoring, we get ...
(2t +1)(t -1) = 0
The positive value of t that makes a factor zero is t = 1.
It will take 1 second for the gymnast to reach the ground.
__
(b) When h = 8, the equation is ...
8 = -16t^2 +8t +8
Subtract 8 and divide by 8 to get ...
0 = -2t^2 +t
0 = t(1 -2t) . . . . factor out t
Values of t that make the factors zero are ...
t = 0
t = 1/2
The gymnast will be 8 feet above the ground at the start of the dismount, and 1/2 second later.
Answer:
Equation: y = -3x -2
Graph: Attached below ↓↓↓↓↓
Step-by-step explanation:
The equation is y = -3x + b
We need B at this point.
Since we have a point given to us,( -2, 4)we can input the x and y
Solve:
4 = -3(-2) + b
4 = 6 + b
b = -2
So the equation we have is y = -3x -2
Let's graph the line.
We go 2 units below the x-axis, because the y-intercept is -2, and the slope is -3, so we go down 3 units, and to the right 1.
Picture attached:
-Chetan K