Hey there!
1. 5(s-2) This is because s-2 is the length of each side, and there are 5 sides in a pentagon all of that length, so multiplying it by 5 like this shows its perimeter.
2. 5s-10 This can be found by distributing the first equation, multiplying both s and -2 by 5.
3. (s-2) + (s-2) + (s-2) + (s-2) + (s-2) Each grouping in the parenthesis represents each of the 5 sides, so adding them all together will get you the perimeter.
4. 5(s) + 5(-2) This one is most like the first one, except it's a little more spread out. Multiply the term s by the 5 sides in one grouping, and the integer -2 by 5 in the other.
Hope this helps!
Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to

.

---> equation (1)
By using pythagoras rule which states that the

---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,

substitute this value in equation (1) then

where A is the area of the square whose side is x
Y=mx+b
y=(1200-2x)/3
y=1200/3-2/3x
y=400-2/3x
y=-2/3x+400
Answer:
a ≠ 2
Step-by-step explanation:
Given

The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that a cannot be, that is
- 3a + 6 = 0 ( subtract 6 from both sides )
- 3a = - 6 ( divide both sides by - 3 )
a = 2 ← excluded value