All categories

3 years ago

1/4 _ 1/5 is it < = >

Mathematics

1 answer:

Gre4nikov [31]3 years ago

4 0

Answer:

1/4 > 1/5

Step-by-step explanation:

think of a candy bar. if you split it into 4 parts the prices would be bigger than if u had to break it into 5 parts. also remember that the smaller number eats the bigger number so the sign would be towards the 1/4

You might be interested in

Write an Algebraic Expression to represent "Five Plus the Quotient of r and 14"

LenKa [72]

Rewriting the function as an equation y=r,14"
5+r/14

5 0

4 years ago

Please Help! Simple Geometry!

marta [7]

Answer:

A 32.1

Step-by-step explanation:

Given two points $(x_{1} ,y_{1} ) and (x_{2} ,y_{2})$ )

distance between to points = d = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} )^{2} }$

Now B is (-4,5) and A is (2,0)

So AB = $\sqrt{(-4-2)^{2} +(5-0)^{2} } = \sqrt{36 + 25} = \sqrt{61\\} = 7.810...$

C is (4,10)

So BC = $\sqrt{(-4-4)^{2} +(5-10)^{2} } =\sqrt{64 + 25) } =\sqrt{89} =9.433...$

D is (8,7)

So CD = $\sqrt{(4-8)^{2} +(10-7)^{2} } =\sqrt{16 + 9} = \sqrt{25} = 5$

E is (4,5)

So DE = $\sqrt{(8-4)^{2} + (7-5)^{2} } = \sqrt{16 + 4} = \sqrt{20} = 4.472...$

and AE = $\sqrt{(4-2)^2 + (5-0)^2} =\sqrt{4+25} = \sqrt{29} = 5.385...$

Perimeter = 7.810 + 9.433 + 5 + 4.472 + 5.385 = 32.1

7 0

3 years ago

Can someone help me make it a mixed number

Dafna11 [192]

1: Multiply:
4x6=24
Then
Add:
24+5=29

6 0

3 years ago

Read 2 more answers

What is the property of (9×5)d

andrey2020 [161]

Associative property of multiplication
(note, ab means a times b)

a(bc)=(ab)c

allows us to move parenthasees around when all multiplying

6 0

3 years ago

Show that the two triangles ABC and DEF are congruent by the HL theorem.

inna [77]

Since hypotenuses and legs have the same length, then both are congruent and thus, triangles ABC and DEF are congruent.

The Hypotenuse-Leg theorem states that two right triangles are congruent if and only if their hypotenuses and any of their corresponding legs are congruent. That is to say:

$\overline {AC} \cong \overline {DF}$ , $\overline{BC} \cong \overline {EF}$