How many boys are there in a group of 27 students if there are four-fifths as many girls as there are boys?

Mathematics

1 answer:

tekilochka [14]3 years ago

4 0

Answer:

15 boys

Step-by-step explanation:

There are 27 students. The number of girls is only 4/5 of the number of boys. I started by splitting the class. 14 boys and 13 girls doesn't work, so I changed it to 12 and 15. If it was 12 girls and 15 boys, the girls would have 4/5 of the boys, so it must be 12 girls and 15 boys.

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Anna11 [10]

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Step-by-step explanation:

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nalin [4]

Answer:

5x -7y = 21

Step-by-step explanation:

A sketch can convince you that BC is a transversal perpendicular to parallel lines AB and CD. The question asks for an equation for CD, so we just need to write the equation of a line through D that is parallel to AB.

One way to do this is to equate the slopes of the parallel lines:

∆y/∆x for AB = ∆y/∆x for CD

(y2 -y1)/(x2 -x1) = (y -2)/(x -7) . . . . . . where (x1, y1) = A; (x2, y2) = B; (7, 2) = D

(4 -(-1))/(1 -(-6)) = (y -2)/(x -7)

5(x -7) = 7(y -2) . . . . . . . . . . . . . cross multiply

5x -7y = 21 . . . . . . . . . . . . . . . . add 35 -7y, simplify

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Note that the graph shows the line CD is named "b", and its equation is shown at upper left. Multiplying that equation by -1 gives the one shown here.