Answer:
Given a square ABCD and an equilateral triangle DPC and given a chart with which Jim is using to prove that triangle APD is congruent to triangle BPC.
From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.
Therefore, the justification to complete Jim's proof is "SAS postulate"
Step-by-step explanation:
Answer:
x=3/7
Step-by-step explanation:
x+4 5/7 = 12x
4 5/7 = 11x
x = 3/7
D=y2-y1
D+y1= y2-y1+y1 add y1 to both sides to cancel it out.
D+y1=y2 that drops -y1 for the right side but the left remains.
And that's your answer.
9/11 is equal to 18/22, so then D.
Answer:
A. I can't quite see the question, but I'm pretty sure it's A
Step-by-step explanation:
Sin(A) = 1/3
Sin^2(A) + Cos^2(A) = 1
(1/3)^2 + cos^2(A) = 1
1/9 + cos^2(A) = 1
cos^2(A) = 1 - 1/9
cos^2(A) = 8/9
cos(A) = √(8/9)
√8 = √(2 * 2 * 2) = 2√2
√9 = 3
cos(A) = 2√2/3
