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3 years ago

PLS HELP- ill do 15 points T-T MATH

Mathematics

1 answer:

True [87]3 years ago

7 0

Answer:

No solution

Step-by-step explanation:

In order for a system of equations to have a solution they must intersect at some point

The two equation shown are parallel

Parallel lines never touch therefore there is no solution

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Please Help? A circle has an arc length of 5π in. The central angle for this arc measures π/3 radians. What is the area of the a

Zielflug [23.3K]

Answer:

The area of the associated sector is $\frac{25}{24}\pi \ in^{2}$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

$C=2\pi r$

we have

$C=5\pi\ in$

substitute and solve for r

$5\pi=2\pi r$

$r=2.5\ in$

step 2

Find the area of the circle

we know that

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=2.5\ in$

substitute

$A=\pi (2.5^{2})=6.25\pi\ in^{2}$

step 3

Find the area of the associated sector

we know that

$2\pi\ radians$ subtends the complete circle of area $6.25\pi\ in^{2}$

by proportion

Find the area of a sector with a central angle of $\pi/3\ radians$

$\frac{6.25\pi }{2\pi} =\frac{x}{\pi/3}\\x=6.25*(\pi/3)/2\\ \\x=\frac{25}{24}\pi \ in^{2}$

8 0

3 years ago

How do i make a table of values for each function rule and then graph the function for these examples:

Sholpan [36]

$\bf \begin{array}{ccllll}
y=1.5x-3\\
\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\

x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
-3&1.5(-3)-3\\
-2&1.5(-2)-3\\
-1&1.5(-1)-3\\
0&1.5(0)-3\\
1&1.5(1)-3\\
...&...
\end{array}$ $\bf \begin{array}{ccllll}
y=-x^2+4\\
\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\

x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
-3&-(-3)^2+4\\
-2&-(-2)^2+4\\
-1&-(-1)^2+4\\
0&-(0)^2+4\\
1&-(1)^2+4\\
...&...
\end{array}$

and so on, and then, you graph those x,y coordinates

5 0

3 years ago

What is the square root of 32 over 4

castortr0y [4]

$\frac{\sqrt{32}}{4}$