Answer: JW.org is where you can find your answers.
In this question it is given that
And we have to find the value of the given limit
Using properties of limit, first we separate the two functions, that is
Substituting the values of the given limit,
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>
Answer:
A. (2x-3)/2
Step-by-step explanation:
Performing the long division indicated by the perimeter expression, you find ...
perimeter = (2x -3) + (10x +6)/(x^2 +2x)
Comparing this to the formula for the perimeter ...
perimeter = 2W +2L
where L is said to be of the form (ax +b)/(x^2 +2x)
we can match terms in the perimeter expression to see that ...
2W = 2x -3
2L = (10x +6)/(x^2 +2x)
The problem doesn't ask for it, but we can see that (a, b) = (5, 3). We can also see that ...
W = (2x -3)/2 . . . . . . . matches choice A
Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
To begin with, let's establish that ( x ) can equal to any number from 0 to 9.
Meaning, that ( x ) is equal to one of the following: 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9.
Now that we know which values ( x ) can equal to, we will simply substitute each of the numbers as potential values of ( x ) into the six-digit number and divide it by 27 to see if it is a multiple of 27.
If X = 0
= 63X904 / 27
= 630904 / 27
= Not a whole number
Therefore, X is not equal to 0.
If X = 1
= 63X904 / 27
= 631904 / 27
= Not a whole number
Therefore, X is not equal to 1.
If X = 2
= 63X904 / 27
= 632904 / 27
= Not a whole number
Therefore, X is not equal to 2.
If X = 3
= 63X904 / 27
= 633904 / 27
= Not a whole number
Therefore, X is not equal to 3.
If X = 4
= 63X904 / 27
= 634904 / 27
= Not a whole number
Therefore, X is not equal to 4.
If X = 5
= 63X904 / 27
= 635904 / 27
= 23552
ANSWER:
Therefore, the answer is:
X = 23, 552
Please mark as brainliest if you found this helpful! :)
Thank you <3
