Answer:
1.4 or in fraction form 7/5
Step-by-step explanation:
Hope this is what you were looking for
Answer:
A
Step-by-step explanation:
This is exponential decay; the height of the ball is decreasing exponentially with each successive drop. It's not going down at a steady rate. If it was, this would be linear. But gravity doesn't work on things that way. If the ball was thrown up into the air, it would be parabolic; if the ball is dropped, the bounces are exponentially dropping in height. The form of this equation is
, or in our case:
, where
a is the initial height of the ball and
b is the decimal amount the bounce decreases each time. For us:
a = 1.5 and
b = .74
Filling in,

If ww want the height of the 6th bounce, n = 6. Filling that into the equation we already wrote for our model:
which of course simplifies to
which simplifies to

So the height of the ball is that product.
A(6) = .33 cm
A is your answer
Answer:
D
Step-by-step explanation:
you need to first do 5.89- [(5.89 * 15)/100]=5.89-0.8835=5.0065
then 5.0065 * 2 = 10.013 because it is 15% each dozen then
[(10.013 * 5)/100] =0.50065 then 10.013 - 0.50065 = 9.51235
and lastly (9.51235 * 7)/100 = 0.6658645
finally 9.51235 + 0.6658645= 10.1782145
and then you just need to round it to the nearest hundredths and you will get 10.18
Answer:
9 units.
Step-by-step explanation:
Let us assume that length of smaller side is x.
We have been given that the sides of a quadrilateral are 3, 4, 5, and 6. We are asked to find the length of the shortest side of a similar quadrilateral whose area is 9 times as great.
We know that sides of similar figures are proportional. When the proportion of similar sides of two similar figures is
, then the proportion of their area is
.
We can see that length of smaller side of 1st quadrilateral is 3 units, so we can set a proportion as:




Take positive square root as length cannot be negative:


Therefore, the length of the shortest side of the similar quadrilateral would be 9 units.
Answer:
x=15º
Step-by-step explanation:
A triangle's angles add up to 180º.
∠A=30º
∠C=180º-45º
∠B=xº
To find ∠B we have to first find ∠C.
Since ∠C does not have an angle, knowing that a straight line is 180º we can subtract it from 45º to find ∠C.
180-45=135
∠C=135º
Now add ∠A and ∠C.
30+135=165
Subtract the sum from 180º
180-165=x
x=15º
Hope this helps :)