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3 years ago

How many cubes with side lengths of 1/4 does it take to fill this prism?

Mathematics

1 answer:

Zinaida [17]3 years ago

3 0

Answer:

Step-by-step explanation:

There isn’t a picture its all black

Try to fix that lol

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Use the following table below, which represents the average rainfall in Orlando to answer this questions:

MariettaO [177]

Answer:

me no understand plz ask a teacher

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3 years ago

A triangle has the coordinates

Romashka-Z-Leto [24]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , thus

A(4, - 1 ) → A'(- 4, - 1 )

B(3, - 3 ) → B'(- 3, - 3 )

C(0, 2 ) → C'(0, 2 )

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3 years ago

What is 432*80? Show your work by multiplying with zeros

Dima020 [189]

Answer:

in the steps

Step-by-step explanation:

do 432*8 then just add a 0

3 0

3 years ago

Read 2 more answers

How do I determine the range.

Nikitich [7]

Answer:

y: (5, -5)

Step-by-step explanation:

5 0

3 years ago

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

3 years ago