I need help with These two questions.(nothing is missing)

2 answers:

frez [133]3 years ago

8 0

Answer:

1.)B

2.A

Step-by-step explanation:

anyanavicka [17]3 years ago

4 0

Answer:

B and A

Step-by-step explanation:

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NISA [10]

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Step-by-step explanation:

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3 years ago

motikmotik

Answer:

wow that is a lot

Step-by-step explanation:

maybe you should send it in bits not all at once

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4 years ago

I am Lyosha [343]

-5 Subtract 8 from -12 and divide -20 by 4 and get -5

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3 years ago

Nata [24]

Since both have same speed
v(rel.) x-(-x)= 10( from law of vector addition)
2x=10,x= 5m/sec

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3 years ago

Dvinal [7]

The value remains under the radical is 8 ⇒ last answer

Step-by-step explanation:

Let us revise how to write the exponent as a radical

Example:

$(54)^{\frac{2}{3}}=\sqrt[3]{(54)^{2}}$ ,
Factorize 54 into prime factors ⇒ 54 = 2 × 3 × 3 × 3 = $2(3)^{3}$
$\sqrt[3]{(54)^{2}}=\sqrt[3]{[2(3^{3}]^{2}}=\sqrt[3]{2^{2}*3^{6}}$
2² can not go out the radical because 2 is less than 3 not divisible by 3
$3^{6}$ can go out the radical because 6 is divisible by 3, then divide 6 by 3, so it will be 3² out the radical
$\sqrt[3]{(54)^{2}}=3^{2}\sqrt[3]{2^{2}}=9\sqrt[3]{4}$