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seropon [69]
3 years ago
7

Function that has Domain: x≠-1 Range: y≠2

Mathematics
1 answer:
Degger [83]3 years ago
4 0
I don't understand your question.
You might be interested in
7. Mahmoud runs to a marker and back in 15 minutes. His speed on
blsea [12.9K]

Answer:

2000 meters

Step-by-step explanation:

From the above question

Total time = 15 minutes

Converting minutes to seconds

1 minute = 60 sec

15 minutes = x

Cross Multiply

x = 60 × 15 = 900 seconds

Hence, 900 seconds = Total time

Total time = Time to the marker + Time from the marker

From the question, we are given the Speed to the marker = 5 m/s

Speed from the marker = 4 m/s

Time = Distance/speed

Let the distance be represented by x

Hence:

x/4 + x/5 =900

Multiply all through equation by Lowest Common Denominator = 20

5x + 4x= 900×20

9x = 900 ×20

Divide both sides by 9

9x/9 = 900 × 20/9

x = 2000 meters

Therefore, the total distance to the marker = 2000 meters

3 0
3 years ago
What is 7 divided by 1/2?
skad [1K]
7 / (1/2)...when dividing with fractions, flip what u r dividing by, then multiply
7 * 2/1 = 14/1 or just 14
7 0
3 years ago
Help me find the area
Assoli18 [71]
If you can add the dimensions, then I will edit this answer to actually be helpful.
8 0
4 years ago
Find the average rate of change for the function f(x)=32 + 25
mixas84 [53]

given the function, there is no independent variable, x. Because of that your equation remains constant at the y axis, where you get f(x)=57. This means that for any input of x you’ll get 57 as the output. Because youre looking for average rate of change, you would use delta y/ delta x.

(2,57) and (6,57)

When you solve for change between the y and x, you get (57-57)/(6-2
) which ultimately gives you an average rate of change of 0.

5 0
3 years ago
If f(x)=8-5x, find each value<br> 1. f(4c)<br> 2. f(2-k)<br> 3. f(4p+3)<br> Please and thanks!
Studentka2010 [4]

Problem 1

We replace every copy of x with 4c and simplify like so:

f(x) = 8 - 5x

f(4c) = 8 - 5*4c

f(4c) = 8 - 20c is the answer

This is equivalent to -20c+8.

====================================================

Problem 2

Same idea as before, but this time we'll plug in x = 2-k

Each x gets replaced with (2-k)

f(x) = 8 - 5x

f(2-k) = 8 - 5(2-k)

f(2-k) = 8 - 10 + 5k

f(2-k) = -2 + 5k

This is the same as saying 5k - 2.

====================================================

Problem 3

The steps are similar to earlier.

f(x) = 8 - 5x

f(4p+3) = 8 - 5(4p+3)

f(4p+3) = 8 - 20p - 15

f(4p+3) = -7-20p

This is the same as writing -20p - 7.

7 0
2 years ago
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