What is the probability of getting exactly 5 “heads” in 10 coin flips ?

2 answers:

6 0

There are $\dbinom{10}5=\dfrac{10!}{5!(10-5)!}=252$ ways of getting exactly 5 heads in 10 tosses. There are $2^{10}=1024$ possible outcomes. So the probability of getting exactly 5 heads is

$\dfrac{252}{1024}=\dfrac{63}{256}\approx24.61\%$

VladimirAG [237]3 years ago

4 0

Answer:

the answer is 63/256 or b

Step-by-step explanation:

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