Answer:
50 quarters and 28 nickels
Step-by-step solution:
We have two variables we are solving for. We will call them Q for the number of quarters and N for the number of nickels.
We know that the total number of coins is equal to 78, and we know that the total amount the coins are worth is equal to $13.90. With this information, we can set up a system of equations:
Q + N = 78
0.25Q + 0.05N = 13.90
Now we can solve for either Q or N in the first equation and solve by substitution by plugging the value into the second equation. Let's solve for Q:
Q = 78 - N
Now plug in 78-N for Q:
0.25(78-N) + 0.05N = 13.90
Distribute and combine like terms:
19.50 - 0.25N + 0.05N = 13.90
19.50 - 0.20N = 13.90
-0.20N = -5.60
N = 28
Now we know that there are 28 nickels. We can plug this into one of the original equations to solve for Q:
Q + 28 = 78
Q = 50
There are 50 quarters. We can verify our answer by plugging the values for A and N into the other equation (optional step to check work):
0.25(50) + 0.05(28) = 13.90
12.5 + 1.40 = 13.9
13.9 = 13.9
Our answer is correct.
Answer:
3 it teaches them a lesson by dont judge someone by how he looks
everyone was judging her cause of her religious and looks and in the end they admired the wall that she had painted cause it teaches them a lesson dont judge a book by it cover
4 Was the painter an “outsider” or a part of the community? Why? she was an outsider she came for a purpose and its to paint the wall text from the story "The painter lady has come to town ostensibly with the purpose of painting a mural."
Answer:
1:12 One sketch every 12 minutes. Four Easy Steps Below!
Step-by-step explanation:
The ratio will be sketches:minutes
*We try to find how many minutes it takes him to make 1 sketch, since it's asking for lowest terms!
- find the larger ratio= 5:60 *60 minutes in an hour, we're finding minutes! Convert one hour to minutes*
- 5:60.... Divide 60 by 5. *You're finding the time it takes for one sketch*
- 12
- 1:12 1 sketch every 12 minutes. This is the lowest term.
Answer:
![x = \frac{22}{3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B22%7D%7B3%7D)
Step-by-step explanation:
Since both CB and ED intersect AD perpendicularly, we can say they are parallel and that ΔACB is similar to ΔAED from Thales intercept theorem. Now, we can set up a proportion from the definition of similar triangles:
![\frac{AB}{AD} = \frac{BC}{DE}](https://tex.z-dn.net/?f=%5Cfrac%7BAB%7D%7BAD%7D%20%20%3D%20%5Cfrac%7BBC%7D%7BDE%7D)
We can say that AD = AB + BD(segment addition postulate) and substitute to get AD = 11. Now we can plug in the numbers we have to the proportion:
![\frac{6}{11} =\frac{4}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B11%7D%20%3D%5Cfrac%7B4%7D%7Bx%7D)
We can cross-multiply to get:
![6x = 44](https://tex.z-dn.net/?f=6x%20%3D%2044)
and divide by 6 to get
![x = \frac{22}{3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B22%7D%7B3%7D)
Answer:
Hey, Dalilah. I hope I'm not too late, but the answer is <u><em>(3,5)</em></u>.
Step-by-step explanation:
You have to use the equation that includes the x value of <em>3</em>.
<em>4x+1</em> only includes x values that are less than <em>3</em>.
<em>2x-1</em> includes x values that are greater than or equal to <em>3</em>.
I plugged <em>3</em> into both of these equations <em>(4x+1; x < 3 & 2x-1; x ≥ 3)</em> in order to see which equation would've been true.
<em>4(3)+1 = 13; 13 < 3 [False] 13 isn't less than 3 -- and 2(3)-1 = 5; 5 ≥ 3 [True] 5 is greater than or equal to 3.</em>
Since the equation <em>2(3)-1; 5≥3</em> is true, you should use this equation. I used <em>Demos</em> in order to graph <em>Y=2(3)-1</em>. At the bottom of that I put <em>x=3</em>, and it showed me <em>(3,5)</em>.
I'll post the pictures for proof and better clarification if this is confusing, love.