Graph each equation by making a table. y = 4
1 answer:
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Answer:
15 square units.
Step-by-step explanation:
To find the area, we must find the width and length of the rectangle. To find the width and length, we need to find the length of AB and the length of BC. We use the distance formula.
AB: A(-8, 3); B(-3, 3).
=
=
=
= 5
BC: B(-3, 3); C(-3, 6).
=
=
=
=
= 3
Now that we have both the width and the length, we can solve for the area using A = lw, where A is the area, l is the length, and w is the width. In this case, l = 5 and w = 3.
A = lw
A = 5 * 3
A = 15
So, the area of the rectangle is 15 square units.
Hope this helps!
Answer:
Step-by-step explanation:
[1] 2x + y = -1
[2] x - 2y = -8 <------- given linear equations
Graphic Representation of the Equations : ----> given in attatchment
y + 2x = -1 -2y + x = -8 < ----- point where they connect is shown in graph
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = 2y - 8
// Plug this in for variable x in equation [1]
[1] 2•(2y-8) + y = -1
[1] 5y = 15
// Solve equation [1] for the variable y
[1] 5y = 15
[1] y = 3
// By now we know this much :
x = 2y-8
y = 3
// Use the y value to solve for x
x = 2(3)-8 = -2
Solution :
{x,y} = {-2,3}
