If there are 36 inches in 1 yard, convert 82 inches to yards.

The following are the temperatures of 10 days in winter in °C. − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 Work out the mean

marissa [1.9K]

The mean temperature of the given data − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 is 1.9

mean= 1.9

The mean, or average, is calculated by adding up the data and dividing by total number of data.

Given data: − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3

Now, mean = $\frac{sum \;of\; observation}{Total \;number \;of \;observation}$

mean = $\frac{(-3)+ 0+10+2+8+(-5)+ (-1)+ 9+2+(-3)}{10}$

= $\frac{19}{10}$

mean= 1.9

Hence, the mean of − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 is 1.9

Learn more about mean here:

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3 0

2 years ago

Mach the Zodiac to the Months (In order of Zodiac) (NO HELP FROM FRIENDS OR INTERNET)

Sergio [31]

Answer:

Virgo:september-october,

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

What is 79 881/1000 as decimal

den301095 [7]

79.881 hope this helps
i might be wrong

6 0

3 years ago

I need help with finding 25 different numbers that add up to 51. It must be a six digit number. Example would be 6+7+5+8+9+6 = 4

USPshnik [31]

What you could do it is. Start adding numbers and once you get close to
6 numbers See if you are close to 51 and switch around the numbers to make it equal 51 hope this helps

6 0

3 years ago

Factorize :3y²-54y+343

arlik [135]

1 In general, given

a

x

2

+

b

x

+

c

ax

2

+bx+c, the factored form is:

a

(

x

−

b

+

b

2

−

4

a

c

2

a

)

(

x

−

b

−

b

2

−

4

a

c

2

a

)

a(x−

2a

−b+

b

2

−4ac

)(x−

2a

−b−

b

2

−4ac

)

2 In this case,

a

=

3

a=3,

b

=

−

54

b=−54 and

c

=

343

c=343.

3

(

y

−

54

+

(

−

54

)

2

−

4

×

3

×

343

2

×

3

)

(

y

−

54

−

(

−

54

)

2

−

4

×

3

×

343

2

×

3

)

3(y−

2×3

54+

(−54)

2

−4×3×343

)(y−

2×3

54−

(−54)

2

−4×3×343

)

3 Simplify.

3

(

y

−

54

+

20

3

ı

6

)

(

y

−

54

−

20

3

ı

6

)

3(y−

6

54+20

3



)(y−

6

54−20

3



)

4 Factor out the common term

2

2.

3

(

y

−

2

(

27

+

10

3

ı

)

6

)

(

y

−

54

−

20

3

ı

6

)

3(y−

6

2(27+10

3

)

)(y−

6

54−20

3



)

5 Simplify

2

(

27

+

10

3

ı

)

6

2(27+10

3

)

to

27

+

10

3

ı

3

27+10

3



.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

54

−

20

3

ı

6

)

3(y−

3

27+10

3



)(y−

6

54−20

3



)

6 Factor out the common term

2

2.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

2

(

27

−

10

3

ı

)

6

)

3(y−

3

27+10

3



)(y−

6

2(27−10

3

)

)

7 Simplify

2

(

27

−

10

3

ı

)

6

2(27−10

3

)

to

27

−

10

3

ı

3

27−10

3



.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

27

−

10

3

ı

3

)

3(y−

3

27+10

3



)(y−

3

27−10

3

I hope this help you

6 0

3 years ago