At the end of three days,
% of the original amount of liquid remains in Kyle's container .
<u>Step-by-step explanation:</u>
Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:
Let's suppose initially we have 100% of liquid present so ,
<u>At day 1:</u>
10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
<u>At day 2:</u>
10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
<u>At day 3:</u>
10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :
⇒ 
⇒ 
⇒
%
Therefore , At the end of three days,
% of the original amount of liquid remains in Kyle's container .
400/12 = # of dozen needed
.89 * # of dozen needed
400/12=33.33 need 34 dozen
.89*34=$30.26
Answer:
90 and 30 liters
Step-by-step explanation:
1) if solution of 20% is 'x' and of 60% is 'y' liters, then
2) the pure chlorine is: for solution of 20% - 0.2x, for solution of 60% - 0.6y and
3) the mix of the two solutions is 120=x+y.
4) using these items it is possible to make up the system of two equations:

5) finally, x=90 liters of 20%; y=30 liters of 60% solution.
Answer:
-4
Step-by-step explanation:
2^2 =4
PMDAS
-36 / 4 +5
-9+5
-4