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3 years ago

PLEASE HELP ME!!PLACE THEM IN ORDER FROM LEAST TO GREATEST

Mathematics

1 answer:

Naya [18.7K]3 years ago

3 0

7
_ 0.61 0.95.
8
my 5th grader answered it he needs some help with his math and we saw this question and he wanted to help. So if it's not right I'm sorry it was out of kindness

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4 years ago

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3 years ago

An equilateral triangle has sides 8 units long. An equilateral triangle with sides 4 units long is cut off at the top, leaving a

Darina [25.2K]

Answer:

1:3

Step-by-step explanation:

Please study the diagram briefly to understand the concept.

First, we determine the height of the isosceles trapezoid using Pythagoras theorem.

$4^2=2^2+h^2\\h^2=16-4\\h^2=12\\h=\sqrt{12}\\ h=2\sqrt{3}$ units$

The two parallel sides of the trapezoid are 8 Inits and 4 units respectively.

Area of a trapezoid $=\dfrac12 (a+b)h$

Area of the trapezoid

$=\dfrac12 (8+4)*2\sqrt{3}\\=12\sqrt{3}$ Square Units$

For an equilateral triangle of side length s.

Area $=\dfrac{\sqrt{3}}{4}s^2$

Side Length of the smaller triangle, s= 4 Units

Therefore:

Area of the smaller triangle

$=\dfrac{\sqrt{3}}{4}*4^2\\=4\sqrt{3}$ Square units$

Therefore, the ratio of the area of the smaller triangle to the area of the trapezoid

$=4\sqrt{3}:12\sqrt{3}\\$Divide both sides by 4\sqrt{3}\\=1:3$

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4 years ago