6a: 11x+9
6b: 5y+14
6c: -3c-10
6d: 15x+10y
6e: -2n+13n
6f: 5w-5z
6g: 19x+8y+9
6h: 11a+4b-5
hope this helps and is correct!!
Answer:
Step-by-step explanation:
first we gotta find the slope of the first line
(-4,-3),(4,1)
slope = (y2 - y1) / (x2 - x1) = (1- (-3) / (4 - (-4) = (1 + 3) / (4 + 4) = 4/8 = 1/2
so the slope is 1/2.....so we are looking for a line that is perpendicular....perpendicular lines have negative reciprocal slopes...all that means is flip the slope and change the sign....so the slope we need is :
1/2....flip it....2/1.....change the sign....-2.....we need a -2 slope
y - y1 = m(x - x1)
slope = -2
(-4,3)...x1 = -4 and y1 = 3
now sub
y - 3 = -2(x - (-4) =
y - 3 = -2(x + 4) <=====
Answer:
-1, 2
Step-by-step explanation:
Answer:
(-♾, ♾)
Step-by-step explanation:
A quadratic can accept any real x value. So the domain is All Real Numbers. This in interval notation is
(-♾, ♾)
This is read as negative infinity to positive infinity
