First you should find the area of the rectangle in the middle.
A: 9 x 6 = 54
Then you can find the area of the triangle on the right.
A: 6 x 5 = 30/2 = 15
Then you can do the triangle on the right.
11-9 = 2
A: 2 x 6 = 12/2 = 6
Then you can add it all together.
15 + 6 + 54 = 74
So the area of the irregular shape is 74.
I hope this helps!
Answer:
<u>∠IJG = 123° </u>
Step-by-step explanation:
Since AB║CD, EF ║GH, we can use the Corresponding Angles Postulate, for finding the following congruent angles:
∠IKL ≅ ∠EIJ and ∠EIJ ≅ ∠GJA
∠GJA and ∠IJG are supplementary, therefore:
∠GJA + ∠IJG = 180°
∠IJG = 180° - 57°
<u>∠IJG = 123°</u>
Answer:
D. x = 7 and x = 14
Step-by-step explanation:
this is a quadratic equation, so use the quadratic formula: (-b+-√b^2-4ac) / 2a for ax^2+bx+c=0
If <em>n</em> = 0.151515…, then 100<em>n</em> = 15.151515…
Then
100<em>n</em> - <em>n</em> = 15.151515… - 0.151515…
99<em>n</em> = 15
<em>n</em> = 15/99 = 5/33
