An airplane descends from 15,000 feet at a rate of 200 feet per second.

Mathematics

2 answers:

Evgen [1.6K]3 years ago

8 0

The answer for this question is B.

Sauron [17]3 years ago

7 0

Answer:

The answer should B, only one makes sense

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How can you determine which quadrant an equation falls in?

Sunny_sXe [5.5K]

$\bf 2sec^2(\theta )-tan(\theta )-3=0
\\\\\\
2[1+tan^2(\theta )]-tan(\theta )-3=0\implies 2+2tan^2(\theta )-tan(\theta )-3=0
\\\\\\
2tan^2(\theta )-tan(\theta )-1=0\implies [2tan(\theta )+1][tan(\theta )-1]=0\\\\
-------------------------------\\\\$

$\bf 2tan(\theta )+1=0\implies 2tan(\theta )=-1\implies tan(\theta )=-\cfrac{1}{2}
\\\\\\
\measuredangle \theta \approx
\begin{cases}
5.82\ radians\\
2.68\ radians
\end{cases}\qquad 
\begin{array}{llll}
\textit{the tangent is negative}\\
\textit{tha means the II and IV quadrants}
\end{array}\\\\
-------------------------------\\\\$

$\bf tan(\theta )-1=0\implies tan(\theta )=1\implies \measuredangle \theta =
\begin{cases}
\frac{\pi }{4}\\
\frac{7\pi }{4}
\end{cases}
\\\\\\
\textit{the tangent is positive}\\
\textit{that means the I and III quadrants}$

bear in mind that tangent is sine/cosine or y/x

for the tangent to be negative, the signs of "y" and "x" must differ, and that happens only on the II and IV quadrants

and for the tangent to be positive, the signs must be same, and that's only on I and III quadrants.

8 0

3 years ago

Evaluate the expression. -{-16.9 + 10} PLZ HELP

DaniilM [7]

$Solution, -\left\{-16.9+10\right\}=6.9$