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3 years ago

An airplane descends from 15,000 feet at a rate of 200 feet per second.

Mathematics

2 answers:

Evgen [1.6K]3 years ago

8 0

The answer for this question is B.

Sauron [17]3 years ago

7 0

Answer:

The answer should B, only one makes sense

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5x-1/5=7/3 <br> Find The LCD That would eliminate the fractions

photoshop1234 [79]

Answer:

$x=\frac{7}{15}$

Step-by-step explanation:

$5x-\frac{1}{5} =\frac{7}{3}$

$5x - \frac{3}{15} = \frac{35}{15}$

$5x - \frac{3}{15} + \frac{3}{15} = \frac{35}{15} + \frac{3}{15}$

$5x=\frac{35}{15}$

$\frac{5x}{5} } =\frac{\frac{35}{15}}{5}$

$x=\frac{7}{15}$

7 0

2 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

In the diagram, think of each segment in the figure as part of a line.

Otrada [13]

Answer:

m and k

Step-by-step explanation:

4 0

3 years ago

A weather station on the top of a mountain reports that the temperature is currently 0 degrees Celsius and has been falling at a

madam [21]

Answer:

The temperature of the weather station was 3 degrees Celcius an hour earlier.

Step-by-step explanation:

We can say that the weather an hour ago should be represented with the variable - x.

From the problem, we know that the temperature of the station falls at a rate of -3 degrees per hour. This means that for every hour, the temperature of the place will go down by about 3 degrees Celsius.

If the temperature of the weather station is currently 0 degrees Celsius, to find its temperature an hour earlier, it means that we will need to add 3 degrees to its current temperature, because that is what must have lost in one hour.

i.e x = 0 + 3 = 3 degrees Celcius.

This means that the temperature of the weather station was 3 degrees Celcius an hour earlier.

5 0

3 years ago

Find X.............

Mrrafil [7]

Your answer is x = 78! Hope this helps!

3 0

3 years ago