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Alik [6]
3 years ago
15

Please help me rn!!!!!

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0
The answer is A, the first one :)
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What is the equation of the line, in point-slope form, that passes through the points (9, 1) and (4, 16)?
Nat2105 [25]

Answer:

<h2>B. y - 1 = -3(x - 9)</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (9, 1) and (4, 16). Substitute:

m=\dfrac{16-1}{4-9}=\dfrac{15}{-5}=-3

y-1=-3(x-9)

6 0
3 years ago
If it is 9:54 pm what time would it be 1 hour and 30 minutes later
3241004551 [841]

Answer:

11:24 pm

Step-by-step explanation:

9:54 pm + 1 hour (60 mins) = 10:54 pm

10:54 + 30 mins = 11:24 pm

5 0
4 years ago
Read 2 more answers
Help please
stepladder [879]

Answer:

The answer is d) 480cm³

Step-by-step explanation:

3 x 10 x 16 = 480cm³

3 0
2 years ago
Need help with math problem don’t understand
MariettaO [177]

Answer:

should be D

Step-by-step explanation:

5 0
3 years ago
Please help me with this question
wlad13 [49]

Answer:

-3

Step-by-step explanation:

Remember the following:

cos(x)=cos(x/2 + x/2) = cos(x/2)*cos(x/2) -sin(x/2)*sin(x/2)

cos(x)=cos2(x/2) - sin2(x/2)

We also know that sin2(a)+cos2(a)=1,

so sin2(x/2)=1 - cos2(x/2). obtained from previous step.

So, our first expression can be written as:

cos(x)=cos2(x/2)-1+cos2(x/2)

Where we obtain that: cos(x/2)= sqrt( 1+ cos(x))/ sqrt(2)

If we again use sin2(a)+cos2(a)=1, we will obtain the following relation:

sin(x/2)= sqrt(1-cos(x))/sqrt(2)

Next Tang(x/2)= sin(x/2) / cos(x/2)= sqrt(1-cos(x))/sqrt(1+cos(x))=

SQRT(9/1)=3

In the given range, cos(x), hence tan(x/2) is also negative

6 0
3 years ago
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