To find it it is
ax^2+bx+c
if the first term (a) is 1 then c=b/2
b=-1/4
(-1/4)/2=-1/4 times 1/2=-1/8
k=-1/8
2) -88, -45, 5, 40
4) -45, -31, 20, 49
6) -74, -63, -45, 38
8) 18, 27, 27, 58
10) -60, -49, -40, 9
12) -45, -18, 80, 82
The bigger negative numbers are the least because negative numbers work the opposite way around of positive numbers. :)
Answer:
D) Only (-1,9) is a solution.
Step-by-step explanation:
x+y =8
x^2 + y = 10
Lets check the first point (-1,9)
Put in x =-1 y =9
x+y =8
-1+9 = 8
8 =8
This works
x^2 + y = 10
(-1)^2 +9 =10
1+9 = 10
10 = 10
This works
Lets check the second point (-2,6)
Put in x =-2 y =6
x+y =8
-2+6 = 8
4=8
This does not work
We can stop now. (-2,6) cannot be a solution
Domain: [-4,4] (left-to-right or x-values used)
Range: [-4,4] (down-to-up or y-values used)
Function: no
