Here you're being asked to find the "perimeter" of the space, even tho' the problem doesn't specifically ask for it.
The formula for P is P = 2W + 2L.
Here the width, W, is 3 1/2 yds, and the length, L, is 4 2/3 yds. Subbing these two values into the formula for P (above) results in:
P = 2(3 1/2 yds) + 2(4 2/3 yds)
= 7 yds + 9 1/3 yds = 16 1/3 yds, total.
Answer:
6
Step-by-step explanation:
Any circle in the form
Where r^2 is the radius squared, so
2 2/3=8/3 and 1 1/3=4/3. 8/3×4/3=32/9. 32/9 as a mixed number is 3 5/9.
Answer: 24
Step-by-step explanation: The triangle is a 45-45-90. It’s an isosceles triangle
Answer:
28.740,
Step-by-step explanation:
