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4 years ago

What is the GCF of 60 and 55?

Mathematics

2 answers:

Ymorist [56]4 years ago

4 0

Answer:

Step-by-step explanation:

anygoal [31]4 years ago

4 0

Answer:

Step-by-step explanation:

5*12=60

5*11=55

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a five inch bamboo shoot doubles in height every three days. If the equation y=ab to the x power, where x represents the number

PtichkaEL [24]

This question was once asked before so I will put it here.

The correct answer for the question that is being presented above is this one: "x = 2; a = 5; b = 3" A 5 inch tall bamboo shoot doubles in height every 3 days. If the equation y=ab^x, where x is the number of doubling periods, represents the height of the bamboo shoot.

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3 years ago

Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k.<br> k=______.

LenKa [72]

Answer:

Step-by-step explanation:

Look at one of the coordinates to find k. For this example I'll look at the y-intercepts (0, 3) (for g(x)) and (0, -2) (for f(x))

g(0) = 3

g(0) = f(0) + k

3 = -2 + k

5 = k

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2 years ago

Please help me with my math

WARRIOR [948]

Mainly all you do is subtract , and it'll give you the right estimate

4 0

3 years ago

What is the factor of 31

Novosadov [1.4K]

Answer:

1 and 31

Step-by-step explanation:

They both divide by it's self to get the same number.

6 0

3 years ago

Read 2 more answers

A roulette wheel has the numbers 1 through 36, 0, and 00. A bet on three numbers pays 11 to 1 (that is, if you bet $1 and one of

OLga [1]

Answer:

You are expected to lose $0.05 (or win -$0.05)

Step-by-step explanation:

Since the roulette wheel has the numbers 1 through 36, 0, and 00, there are 38 possible outcomes.

In this bet, you are allowed to pick 3 out of the 38 numbers. Thus, your chances of winning (P(W)) and losing (P(L)) are:

$P(W)=\frac{3}{38}\\P(L) = 1 - P(W)\\P(L) = \frac{35}{38}\\$

The expected value of the bet is given by the sum of the product of each outcome pay by its probability. Winning the bet means winning $11 while losing the bet means losing $1. The expected value is:

$EV = (11*\frac{3}{38}) -(1*\frac{35}{38})\\EV = -\$0.0525$

Therefore, with a $1 bet, you are expected to lose roughly $0.05

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3 years ago