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solong [7]
4 years ago
5

2/5÷4 CAN SOMEONE HELP ME PLSSSSS

Mathematics
2 answers:
AleksandrR [38]4 years ago
6 0

Answer:

3/20

The drawing will help

Doss [256]4 years ago
5 0

Answer:

Eight fifths or 1 and three fifths

Step-by-step explanation:

2/5= two fifths

Two fifths x 4 is eight fifths or 1 and three fifths

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Is x = 0 a valid potential solution to the equation log(x + 7) + log(x − 3) = 17?
SpyIntel [72]

Answer:

C ni, because 17 isn't divisible by 7 it 3

5 0
3 years ago
Which is not a characteristic of the absolute value parent function
timama [110]

Answer:

The answer is the option B

the range is all real numbers

Step-by-step explanation:

we know that

the absolute value parent function is equal to

f\left(x\right)=\left|x\right|

see the attached figure to better understand the problem

so

A. it is v-shaped ------> Is true

B. the range is all real numbers ------> Is not true

Because the range is the interval------> [0,∞)

y\geq 0

All real numbers greater than or equal to zero

C. it goes through the origin -----> is true

D. the domain is all real numbers -----> is true

7 0
3 years ago
Evaluating functions
Liono4ka [1.6K]

Step-by-step explanation:

Hope this helps please like and mark as brainliest

7 0
3 years ago
Timothy’s mom bought 7/8 of a pound of grapes. She wants to split it between 8 kids. What fraction of the grapes will each kid g
I am Lyosha [343]

Answer:

Option B

7/64

Step-by-step explanation:

Since the she bought 7/8 of a pound of grapes, the amount of grapes that Timothy's mum will be sharing is only 7/8 of a pound

Total number of kids = 6

To get the amount that each kid will get, we will have to divide 7/8 by 6

Hence we have

\frac{7}{8} \times \frac{1}{6}= \frac{7}{64}

Hence, each child will get 7/64 of a pound of grapes, if the grapes are shared equally.

8 0
4 years ago
Read 2 more answers
Solve to find x <br> log (3x+5) to base 5= 2log (1-3x) to base 25
Eduardwww [97]

Answer:

x = -2/ 3

Step-by-step explanation:

in order to cancel out the logs they should have common bases

\mathsf{ log_{5}(3x + 5) = 2 log_{25}(1 - 3x)  }

we can write 25 as 5²

\mathsf{ \implies  log_{5}(3x + 5) =  2 \: log_{ {5}^{2} }(1 - 3x)  }

we know that the reciprocal of the exponents of the bases are multiplied to the log

\mathsf{ \implies  log_{5}(3x + 5) =   \frac{1}{\cancel{2} } \times \cancel{2} \: log_{ 5}(1 - 3x)  }

and now since the logs have common bases

\mathsf{ \implies  \cancel { log_{5}}(3x + 5) = \cancel{ log_{ 5}}(1 - 3x)  }

we're left with

\mathsf{ \implies 3x + 5 = 1 - 3x}

\mathsf{ \implies 9x = -4}

<u>x = -2/ 3</u>

8 0
3 years ago
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