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Maksim231197 [3]
2 years ago
15

Interact if u in k12

Mathematics
2 answers:
brilliants [131]2 years ago
7 0

Answer:

im in k12, hello and how are you on this fine day? :D

Step-by-step explanation:

Inga [223]2 years ago
7 0

Answer:

asdfghjkl

Step-by-step explanation:

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Joanna buys one kilogram of French roast and one kilogram of boxer blend from the Java Hut. Jacob buys two kilograms of French r
larisa86 [58]

Answer: 28


Step-by-step explanation:

add them all of them up then simply  subtract 46 from 18 and youll get your final answer which is 28


hope this helps :)

8 0
2 years ago
NEED HELP ASAP
Gelneren [198K]

Answer:

3/4 mile

Step-by-step explanation:

A = l *w\\\frac{1}{2} = \frac{2}{3} * w\\w = \frac{3}{2} * \frac{1}{2}\\w = 3/4 mile

6 0
3 years ago
Read 2 more answers
Approximately how many degrees are in the measure of an interior angle of a regular eight sided polygon?
yan [13]
135° I think 1080( what the angles add up to) 1080÷8=135°
4 0
3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
2 years ago
50 points but please give a helpful answer &lt;3
Rasek [7]
They are all (SAS)side angle side except for the bottom right one. This is because the question does not give the little ticks to show that one side is the same as the other. It is not good enough to assume they are congruent without proof.
8 0
3 years ago
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